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2 câu trả lời 328
`P=(x+3)/(x+1)+(2x-1)/(x-1)+(x+5)/(x^2-1)` `(x \ne +-1)`
`=((x+3)(x-1))/((x+1)(x-1))+((2x-1)(x+1))/((x-1)(x+1))+(x+5)/((x-1)(x+1))`
`=(x^2+2x-3+2x^2+x-1+x+5)/((x-1)(x+1))`
`=(3x^2+4x+1)/((x-1)(x+1))`
`=(3x^2+3x+x+1)/((x-1)(x+1))`
`=((3x+1)(x+1))/((x-1)(x+1))`
`=(3x+1)/(x-1)`
P=x+3x+1+2x−1x−1+x+5x2−1P=x+3x+1+2x-1x-1+x+5x2-1 (x≠±1)(x≠±1)
=(x+3)(x−1)(x+1)(x−1)+(2x−1)(x+1)(x−1)(x+1)+x+5(x−1)(x+1)=(x+3)(x-1)(x+1)(x-1)+(2x-1)(x+1)(x-1)(x+1)+x+5(x-1)(x+1)
=x2+2x−3+2x2+x−1+x+5(x−1)(x+1)=x2+2x-3+2x2+x-1+x+5(x-1)(x+1)
=3x2+4x+1(x−1)(x+1)=3x2+4x+1(x-1)(x+1)
=3x2+3x+x+1(x−1)(x+1)=3x2+3x+x+1(x-1)(x+1)
=(3x+1)(x+1)(x−1)(x+1)=(3x+1)(x+1)(x-1)(x+1)
=3x+1x−1
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