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2 câu trả lời 477
\[\begin{array}{l}
5)\left( {\frac{1}{{\sqrt x + 3}} + \frac{{\sqrt x + 9}}{{x - 9}}} \right)\frac{{\sqrt x }}{2}\\
dk:x \ge 0;x \ne 9\\
= (\frac{{\sqrt x - 3}}{{(\sqrt x + 3)(\sqrt x - 3)}} + \frac{{\sqrt x + 9}}{{(\sqrt x + 3)(\sqrt x - 3)}}].\frac{{\sqrt x }}{2}\\
= \frac{{\sqrt x - 3 + \sqrt x + 9}}{{(\sqrt x + 3)(\sqrt x - 3)}}.\frac{{\sqrt x }}{2}\\
= \frac{{2\sqrt x + 6}}{{(\sqrt x + 3)(\sqrt x - 3)}}.\frac{{\sqrt x }}{2}\\
= \frac{{2(\sqrt x + 3)}}{{(\sqrt x + 3)(\sqrt x - 3)}}.\frac{{\sqrt x }}{2}\\
= \frac{{\sqrt x }}{{\sqrt x - 3}}\\
6)\frac{{2x - \sqrt x + 2}}{{x - 4}} + \frac{1}{{\sqrt x + 2}} - \frac{{\sqrt x }}{{\sqrt x - 2}}\\
dk:x \ge 0;x \ne 4\\
= \frac{{2x - \sqrt x + 2}}{{(\sqrt x - 2)(\sqrt x + 2)}} + \frac{{\sqrt x - 2}}{{(\sqrt x - 2)(\sqrt x + 2)}} - \frac{{\sqrt x (\sqrt x + 2)}}{{(\sqrt x - 2)(\sqrt x + 2)}}\\
= \frac{{2x - \sqrt x + 2 + \sqrt x - 2 - x - 2\sqrt x }}{{(\sqrt x - 2)(\sqrt x + 2)}}\\
= \frac{{x - 2\sqrt x }}{{(\sqrt x - 2)(\sqrt x + 2)}}\\
= \frac{{\sqrt x (\sqrt x - 2)}}{{(\sqrt x - 2)(\sqrt x + 2)}}\\
= \frac{{\sqrt x }}{{\sqrt x + 2}}
\end{array}\]
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