Question

Đã trả lời bởi chuyên gia

Answer 1

Khi x= 36

A= $\frac{\sqrt{36} - 2}{\sqrt{36} - 1} - \frac{\sqrt{36} + 2}{\sqrt{36} - 2} + \frac{6 \times \sqrt{36} - 8}{36 - 3 \times \sqrt{36} + 2} = \frac{4}{5} - \frac{8}{4} + \frac{7}{5} = \frac{1}{5}$

Answer 2

$A = \frac{(\sqrt{x} - 2) (\sqrt{x} - 2)}{x - 3 \sqrt{x} + 2} - \frac{(\sqrt{x} + 2) (\sqrt{x} - 1)}{x - 3 \sqrt{x} + 2} + \frac{6 \sqrt{x} - 8}{x - 3 \sqrt{x} + 2} (x \geq 0; x k á c 1; x k h á c 4) = \frac{\sqrt{x} - 2}{(\sqrt{x} - 2) (\sqrt{x - 1})} = \frac{1}{\sqrt{x} - 1}$

Khi x=36 => A= $\frac{1}{\sqrt{36} - 1} = \frac{1}{5}$

P= $\frac{4 \sqrt{x} - 13}{{(\sqrt{x} - 1)}^{2}}$

P max => $\sqrt{x} - 1 n h ỏ n h ấ t$ => x=0

=> Pmax = -13

...Xem thêm

Answer 3

$A = \frac{(\sqrt{x} - 2) (\sqrt{x} - 2)}{x - 3 \sqrt{x} + 2} - \frac{(\sqrt{x} + 2) (\sqrt{x} - 1)}{x - 3 \sqrt{x} + 2} + \frac{6 \sqrt{x} - 8}{x - 3 \sqrt{x} + 2} (x \geq 0; x k á c 1; x k h á c 4) = \frac{\sqrt{x} - 2}{(\sqrt{x} - 2) (\sqrt{x - 1})} = \frac{1}{\sqrt{x} - 1}$

Khi x=36 => A= $\frac{1}{\sqrt{36} - 1} = \frac{1}{5}$

P= $\frac{4 \sqrt{x} - 13}{{(\sqrt{x} - 1)}^{2}}$

P max => $\sqrt{x} - 1 n h ỏ n h ấ t$ => x=0

=> Pmax = -13

Answer 4

2. A=

$\frac{\sqrt{x} - 2}{\sqrt{x} - 1} - \frac{\sqrt{x} + 2}{\sqrt{x} - 2} + \frac{6 \sqrt{x} - 8}{x - 3 \sqrt{x} + 2} = \frac{\sqrt{x} - 2}{\sqrt{x} - 1} - \frac{\sqrt{x} + 2}{\sqrt{x} - 2} + \frac{6 \sqrt{x} - 8}{(\sqrt{x} - 2) \times (\sqrt{x} - 1)} = \frac{(\sqrt{x} - 2) \times (\sqrt{x} - 2)}{(\sqrt{x} - 1) \times (\sqrt{x} - 2)} - \frac{(\sqrt{x} + 2) \times (\sqrt{x} - 1)}{(\sqrt{x} - 2) \times (\sqrt{x} - 1)} + \frac{6 \sqrt{x} - 8}{(\sqrt{x} - 2) \times (\sqrt{x} - 1)} = \frac{x - 4 \sqrt{x} + 4 - (x + \sqrt{x} - 2) + 6 \sqrt{x} - 8}{(\sqrt{x} - 1) \times (\sqrt{x} - 2)} = \frac{\sqrt{x} - 2}{(\sqrt{x} - 1) \times (\sqrt{x} - 2)} = \frac{1}{\sqrt{x} - 1}$

3. B= $\frac{4 \sqrt{x} - 13}{\sqrt{x} - 1}$

$P = A . B = \frac{4 \sqrt{x} - 13}{{(\sqrt{x} - 1)}^{2}}$

P max khi ${(\sqrt{x} - 1)}^{2} m i n \to$ x=0

P max = -13

...Xem thêm

Answer 5

2. A=

$\frac{\sqrt{x} - 2}{\sqrt{x} - 1} - \frac{\sqrt{x} + 2}{\sqrt{x} - 2} + \frac{6 \sqrt{x} - 8}{x - 3 \sqrt{x} + 2} = \frac{\sqrt{x} - 2}{\sqrt{x} - 1} - \frac{\sqrt{x} + 2}{\sqrt{x} - 2} + \frac{6 \sqrt{x} - 8}{(\sqrt{x} - 2) \times (\sqrt{x} - 1)} = \frac{(\sqrt{x} - 2) \times (\sqrt{x} - 2)}{(\sqrt{x} - 1) \times (\sqrt{x} - 2)} - \frac{(\sqrt{x} + 2) \times (\sqrt{x} - 1)}{(\sqrt{x} - 2) \times (\sqrt{x} - 1)} + \frac{6 \sqrt{x} - 8}{(\sqrt{x} - 2) \times (\sqrt{x} - 1)} = \frac{x - 4 \sqrt{x} + 4 - (x + \sqrt{x} - 2) + 6 \sqrt{x} - 8}{(\sqrt{x} - 1) \times (\sqrt{x} - 2)} = \frac{\sqrt{x} - 2}{(\sqrt{x} - 1) \times (\sqrt{x} - 2)} = \frac{1}{\sqrt{x} - 1}$

3. B= $\frac{4 \sqrt{x} - 13}{\sqrt{x} - 1}$

$P = A . B = \frac{4 \sqrt{x} - 13}{{(\sqrt{x} - 1)}^{2}}$

P max khi ${(\sqrt{x} - 1)}^{2} m i n \to$ x=0

P max = -13

3 câu trả lời 218

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