a) x-1x+1+x-3x+2=2
b) 2x+1x+2+x-3x-3=3x2-2x+1x2-x-6
Quảng cáo
2 câu trả lời 105
a)
ĐK: x # -1, x # -2
Ta có
x-1x+1+x-3x+2=2⇔(x-1).(x+2)(x+1).(x+2)+(x-3).(x+1)(x+1).(x+2)=2.(x+1).(x+2)(x+1).(x+2)⇒x2+2x-x-2+x2+x-3x-3=2x2+4x+2x+4⇔7x=-9⇔x=-97 (tm)
a. x-1x+1+x-3x+2=2 (ĐK:x≠-1;x≠-2)
⇔ (x-1)(x+2)(x+1)(x+2)+(x-3)(x+1)(x+1)(x+2)=(2⋅(x+1)(x+2)(x+1)(x+2)
⇔ (x-1)(x+2)+(x-3)(x+1)=(2x+2)(x+2)
⇔ x2+2x-x-2+x2+x-3x-3=2x2+4x+2x+4
⇔ 2x2-x-5-2x2-6x-4=0
⇔ -7x-9=0
⇔ -7x=9
⇔ x=-97 (tmđk)
Vậy S={-97}
---------------
b. 2x+1x+2+x-3x-3=3x2-2x+1x2-x-6 (ĐK:x≠-2;x≠3)
= (2x+1)(x-3)(x+2)(x-3)+(x-3)(x+2)(x+2)(x-3)=3x2-2x+1(x+2)(x-3)
= (2x+1)(x-3)+(x-3)(x+2)=3x2-2x+1
= (x-3)(2x+1+x+2)-3x2+2x-1=0
= (x-3)(3x+3)-3x2+2x-1=0
= -4x-10=0
= -4x=10
= x=-52 (tmđk)
Vậy S={-52}
∘kemnie
Quảng cáo
Câu hỏi hot cùng chủ đề
-
4 98096
-
Hỏi từ APP VIETJACK3 64123
-
1 51199
-
2 43742
-
1 25448
-
2 24892