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2 câu trả lời 489
\[\begin{array}{l}
a,{\rm{ }}7{x^2} + 2x = 0{\rm{ }}\\
\Leftrightarrow x\left( {7x + 2} \right) = 0\\
\Leftrightarrow \left[ \begin{array}{l}
x = 0\\
7x + 2 = 0
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l}
x = 0\\
x = \frac{{ - 2}}{7}
\end{array} \right.\\
Vay:S = \{ 0;\frac{{ - 2}}{7}\} \\
b,{\rm{ }}4{x^2} - {\rm{ }}4x{\rm{ }} = {\rm{ }} - 1\\
\Leftrightarrow 4{x^2} - 4x + 1 = 0\\
\Leftrightarrow {\left( {2x - 1} \right)^2} = 0\\
\Leftrightarrow 2x - 1 = 0\\
\Leftrightarrow x = \frac{1}{2}\\
Vay:x = \frac{1}{2}\\
{\rm{ }}c,{\rm{ }}x\left( {x - 2019} \right){\rm{ }} - {\rm{ }}x{\rm{ }} + {\rm{ }}2019{\rm{ }} = {\rm{ }}0{\rm{ }}\\
\Leftrightarrow x\left( {x - 2019} \right) - \left( {x - 2019} \right) = 0\\
\Leftrightarrow \left( {x - 2019} \right)\left( {x - 1} \right) = 0\\
\Leftrightarrow \left[ \begin{array}{l}
x - 2019 = 0\\
x - 1 = 0
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l}
x = 2019\\
x = 1
\end{array} \right.\\
vay:S = \{ 1;2019\} \\
d,{\rm{ }}{\left( {3x - 4} \right)^2} - {\left( {x{\rm{ }} + {\rm{ }}2} \right)^2}{\rm{ }} = {\rm{ }}0\\
\Leftrightarrow \left( {3x - 4 - x - 2} \right)\left( {3x - 4 + x + 2} \right) = 0\\
\Leftrightarrow \left( {2x - 6} \right)\left( {4x - 2} \right) = 0\\
\Leftrightarrow \left[ \begin{array}{l}
2x - 6 = 0\\
4x - 2 = 0
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l}
x = 3\\
x = \frac{1}{2}
\end{array} \right.\\
vay:S = \{ 3;\frac{1}{2}\}
\end{array}\]
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