1)5/3 - 5a-6/3a.
2)2x/3 + 2ax+3x/3a.
3)2x-3a/2a - 3/2.
4)-5/3b + 9b-25/15b.
5)b/6a + 4a+3b²/18ab - x/9b
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1 câu trả lời 996
\[\begin{array}{l}
1)\frac{5}{3} - \frac{{5{\rm{a}} - 6}}{{3{\rm{a}}}}\\
dk:a \ne 0\\
= \frac{{5{\rm{a}} - 5{\rm{a}} + 6}}{{3{\rm{a}}}}\\
= \frac{6}{{3{\rm{a}}}}\\
= \frac{2}{a}\\
2)\frac{{2{\rm{x}}}}{3} + \frac{{{\rm{2ax + 3x}}}}{{3{\rm{a}}}}\\
dk:a \ne 0\\
= \frac{{{\rm{2ax + 2ax + 3x}}}}{{3{\rm{a}}}}\\
= \frac{{4ax + 3x}}{{3a}}\\
3)\frac{{2x - 3a}}{{2a}} - \frac{3}{2}\\
dk:a \ne 0\\
= \frac{{2x - 3a - 3a}}{{2a}}\\
= \frac{{2x - 6a}}{{2a}}\\
= \frac{{2\left( {x - 3a} \right)}}{{2a}}\\
= \frac{{x - 3a}}{a}\\
4)\frac{{ - 5}}{{3b}} + \frac{{9b - 25}}{{15b}}\\
dk:b \ne 0\\
= \frac{{ - 25 + 9b - 25}}{{15b}}\\
= \frac{{9b - 50}}{{15b}}\\
5)\frac{b}{{6a}} + \frac{{4a + 3{b^2}}}{{18ab}} - \frac{x}{{9b}}\\
dk:a;b \ne 0\\
= \frac{{3{b^2}}}{{18ab}} + \frac{{4a + 3{b^2}}}{{18ab}} - \frac{{2ax}}{{18ab}}\\
= \frac{{3{b^2} + 4a + 3{b^2} - 2ax}}{{18ab}}\\
= \frac{{6{b^2} + 4a - 2ax}}{{18ab}}\\
= \frac{{2\left( {3{b^2} + 2a - ax} \right)}}{{18ab}}\\
= \frac{{3{b^2} + 2a - ax}}{{9ab}}
\end{array}\]
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