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3 câu trả lời 1639
\[\begin{array}{l}
\;a,3\left( {3x - 1/3} \right) = 6\left( {x + 2} \right)\\
{\rm{ = > 9x - 1 = 6x + 12}}\\
{\rm{ = > 9x - 6x = 12 + 1}}\\
{\rm{ = > 3x = 13}}\\
{\rm{ = > x = }}\frac{{13}}{3}{\rm{ }}\\
b,2x - 3 = 3x + 5\left( {x + 1} \right) - 5{\rm{ }}\\
{\rm{ = > 2x - 3 = 3x + 5x + 5 - 5}}\\
{\rm{ = > 2x - 3 = 8x}}\\
{\rm{ = > 8x - 2x = - 3}}\\
{\rm{ = > 6x = - 3}}\\
{\rm{ = > x = }}\frac{{ - 1}}{2}\\
c,x - 1/2 - 1 = 0\\
= > x - \frac{3}{2} = 0\\
= > x = \frac{3}{2}
\end{array}\]
a,3(3x-1/3)=6(x+2)
=>3x-1/3=2.(x+2)
=>3x-1/3=2x+4
=>3x-2x=4+1/3
=>x=13/3
Vậy x=13/3
b,2x-3=3x+5(x+1)-5
=>2x-3=3x+5x+5-5
=>2x-3x-5x=5-5+3
=>-6x=3=>x=-1/2
Vậy x=-1/2
c,x-1/2-1=0
=>x-3/2=0
=>x=3/2
Vạy x=3/2
a,3(3x-1/3)=6(x+2)
=>3x-1/3=2.(x+2)
=>3x-1/3=2x+4
=>3x-2x=4+1/3
=>x=13/3
Vậy x=13/3
b,2x-3=3x+5(x+1)-5
=>2x-3=3x+5x+5-5
=>2x-3x-5x=5-5+3
=>-6x=3=>x=-1/2
Vậy x=-1/2
c,x-1/2-1=0
=>x-3/2=0
=>x=3/2
Vạy x=3/2
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