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2 câu trả lời 389
\(\begin{array}{l}
X - 3/2015 + x - 2/2016 = x - 2016/2 + x - 2015/3\\
\frac{{x - 3}}{{2015}} + \frac{{x - 2}}{{2016}} = \frac{{x - 2016}}{2} + \frac{{x - 2015}}{3}\\
= > \frac{{x - 3}}{{2015}} - 1 + \frac{{x - 2}}{{2016}} - 1 = \frac{{x - 2016}}{2} - 1 + \frac{{x - 2015}}{3} - 1\\
= > \frac{{x - 2018}}{{2015}} + \frac{{x - 2018}}{{2016}} = \frac{{x - 2018}}{2} + \frac{{x - 2018}}{3}\\
= > (x - 2018)(\frac{1}{{2015}} + \frac{1}{{2016}} - \frac{1}{2} - \frac{1}{3}) = 0\\
= > x - 2018 = 0\\
= > x = 2018
\end{array}\)
X-3/2015-1+x-2/2016-1=x-2016/2-1+x-2015/3-1
x-2018/2015+x-2018/2016=x-2018/2+x-2018/3
(X-2018).(1/2015+1/2016-1/2-1/3)=0
x-2018=0
x=2018
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