- \[
\sqrt{\sin^2 x}(1 - \cot x) = \sin x(1 - \frac{\cos x}{\sin x}) = \sin x \left( \frac{\sin x - \cos x}{\sin x} \right) = \sin^2 x - \sin x \cos x
\] (1)

- \[
\cos^2 x(1 - \tan x) = \cos^2 x(1 - \frac{\sin x}{\cos x}) = \cos^2 x \left( \frac{\cos x - \sin x}{\cos x} \right) = \cos^2 x - \sin x \cos x
\] (2)

- \[
-\sqrt{2} \sin^2 x \left(29 - \frac{4}{x}\right) = -29\sqrt{2} \sin^2 x + \frac{4\sqrt{2} \sin^2 x}{x}
\] (3)

\[
C = (\sin^2 x - \sin x \cos x) + (\cos^2 x - \sin x \cos x) - 29\sqrt{2} \sin^2 x + \frac{4\sqrt{2} \sin^2 x}{x}
\]

(1), (2), (3) => \[
C = \sin^2 x + \cos^2 x - 2 \sin x \cos x - 29\sqrt{2} \sin^2 x + \frac{4\sqrt{2} \sin^2 x}{x}
\]

Ta có \(\sin^2 x + \cos^2 x = 1\):
\[
C = 1 - 2 \sin x \cos x - 29\sqrt{2} \sin^2 x + \frac{4\sqrt{2} \sin^2 x}{x}
\]

Vậy
\[
C = 1 - 2 \sin x \cos x - 29\sqrt{2} \sin^2 x + \frac{4\sqrt{2} \sin^2 x}{x}
\]