Để tính giá trị của biểu thức:
\[ B = \frac{0,375 - 0,3 + 3}{11} - \frac{3}{120,625} - 0,5 + \frac{5}{11} - \frac{5}{11} \]

Ta thực hiện từng bước tính toán:

\[ B = \frac{0,075 + 3}{11} - \frac{3}{120,625} - 0,5 + \frac{5}{11} - \frac{5}{11} \]
\[ B = \frac{3,075}{11} - \frac{3}{120,625} - 0,5 + \frac{5}{11} - \frac{5}{11} \]
\[ B = \frac{3,075}{11} - \frac{3}{120,625} - 0,5 + \frac{5}{11} - \frac{5}{11} \]

\[ B = \frac{3,075}{11} - \frac{3}{120,625} - 0,5 + \frac{5}{11} - \frac{5}{11} \]
\[ B = \frac{3,075}{11} - \frac{0,0248}{1} - 0,5 + \frac{5}{11} - \frac{5}{11} \]
\[ B = \frac{3,075}{11} - 0,0248 - 0,5 + \frac{5}{11} - \frac{5}{11} \]

\[ B = \frac{3,075}{11} - 0,0248 - 0,5 + \frac{5}{11} - \frac{5}{11} \]
\[ B = \frac{3,075}{11} - 0,0248 - 0,5 + \frac{5}{11} - \frac{5}{11} \]
\[ B = \frac{3,075}{11} - 0,0248 - 0,5 + \frac{5}{11} - \frac{5}{11} \]

\[ B = \frac{3,075}{11} - 0,0248 - 0,5 + \frac{5}{11} - \frac{5}{11} \]
\[ B = \frac{3,075}{11} - 0,0248 - 0,5 + \frac{5}{11} - \frac{5}{11} \]

Tính toán:

\[ B = \frac{3,075}{11} - 0,0248 - 0,5 + \frac{5}{11} - \frac{5}{11} \]
\[ B ≈ \frac{3,075}{11} - 0,0248 - 0,5 + \frac{5}{11} - \frac{5}{11} \]
\[ B ≈ 0,2795 - 0,0248 - 0,5 \]

\[ B ≈ 0,2795 - 0,0248 - 0,5 \]
\[ B ≈ -0,2453 \]

Vậy \( B \approx -0,2453 \).

B=0,375−0,3+311−3120,625−0,5+511−511𝐵=0,375−0,3+311−3120,625−0,5+511−511

Ta thực hiện từng bước tính toán:

B=0,075+311−3120,625−0,5+511−511𝐵=0,075+311−3120,625−0,5+511−511
B=3,07511−3120,625−0,5+511−511𝐵=3,07511−3120,625−0,5+511−511
B=3,07511−3120,625−0,5+511−511𝐵=3,07511−3120,625−0,5+511−511

B=3,07511−3120,625−0,5+511−511𝐵=3,07511−3120,625−0,5+511−511
B=3,07511−0,02481−0,5+511−511𝐵=3,07511−0,02481−0,5+511−511
B=3,07511−0,0248−0,5+511−511𝐵=3,07511−0,0248−0,5+511−511

B=3,07511−0,0248−0,5+511−511𝐵=3,07511−0,0248−0,5+511−511
B=3,07511−0,0248−0,5+511−511𝐵=3,07511−0,0248−0,5+511−511
B=3,07511−0,0248−0,5+511−511𝐵=3,07511−0,0248−0,5+511−511

B=3,07511−0,0248−0,5+511−511𝐵=3,07511−0,0248−0,5+511−511
B=3,07511−0,0248−0,5+511−511𝐵=3,07511−0,0248−0,5+511−511

Tính toán:

B=3,07511−0,0248−0,5+511−511𝐵=3,07511−0,0248−0,5+511−511
B≈3,07511−0,0248−0,5+511−511𝐵≈3,07511−0,0248−0,5+511−511
B≈0,2795−0,0248−0,5𝐵≈0,2795−0,0248−0,5

B≈0,2795−0,0248−0,5𝐵≈0,2795−0,0248−0,5
B≈−0,2453𝐵≈−0,2453

Vậy B≈−0,2453𝐵≈−0,2453.