Tính a) ( 3/7 + 1/2)^2 b) (3/4 - 5/6)^2 c) 2 : ( 1/2 - 2/3)^3 d) -(2/5) : 1v1/3 - (1/2)^2 f)( 1/2 - 2/3 + 5/6) . (-3/2)^2 e) ( 1 + 2/3 - 1/4) . ( 4/5

An Nam Nguyen Hỏi từ APP VIETJACK

· 13:11 27/08/2022

Tính
a) ( 3/7 + 1/2)^2
b) (3/4 - 5/6)^2
c) 2 : ( 1/2 - 2/3)^3
d) -(2/5) : 1v1/3 - (1/2)^2
f)( 1/2 - 2/3 + 5/6) . (-3/2)^2
e) ( 1 + 2/3 - 1/4) . ( 4/5 - 3/4)^2

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${(\frac{3}{7} + \frac{1}{2})}^{2} = {(\frac{6}{14} + \frac{7}{14})}^{2} = {(\frac{13}{14})}^{2} = \frac{169}{196} b, {(\frac{3}{4} - \frac{5}{6})}^{2} = {(\frac{9}{12} - \frac{10}{12})}^{2} = {(\frac{- 1}{12})}^{2} = \frac{1}{144} c, 2 \div {(\frac{1}{2} - \frac{2}{3})}^{3} = 2 \div {(\frac{3}{6} - \frac{4}{6})}^{3} = 2 \div {(\frac{- 1}{6})}^{3} = 2 \times \frac{6^{3}}{- 1^{3}} = - 2 \times 6^{3} = - 432 d, - (\frac{2}{5}) \div 1 \frac{1}{3} - {(\frac{1}{2})}^{2} = \frac{- 2}{5} \div \frac{4}{3} - \frac{1}{4} = \frac{- 2}{5} \times \frac{3}{4} - \frac{1}{4} = \frac{- 3}{10} - \frac{1}{4} = \frac{- 6}{20} - \frac{5}{20} = \frac{- 11}{20} f, (\frac{1}{2} - \frac{2}{3} + \frac{5}{6}) . {(\frac{- 3}{2})}^{2} = (\frac{3}{6} - \frac{4}{6} + \frac{5}{6}) . \frac{9}{4} = \frac{4}{6} . \frac{9}{4} = \frac{3}{2} e, (1 + \frac{2}{3} - \frac{1}{4}) . {(\frac{4}{5} - \frac{3}{4})}^{2} = (\frac{12}{12} + \frac{8}{12} - \frac{3}{12}) . {(\frac{16}{20} - \frac{15}{20})}^{2} = \frac{17}{12} . {(\frac{1}{20})}^{2} = \frac{17}{12 \times 20^{2}} = \frac{17}{4800}$