Tìm GTNN của A=-4xy-12y+2x+2021
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4 câu trả lời 1077
`A=2x^2+4y^2-4xy-12y+2x+2021`
`A=(2y-x)^2-6(2y-x) +x^2-4x+2021`
`A=(2y-x)^2+6(2y-x) +9+x^2-4x+4+2008`
`A=(2y-x+3)^2+(x-2)^2+2008≥2008`
`Amin=2008` khi `x=2`
`y=1/2`
A=2x2+5y2+4xy−8x+4y+2020A=2x2+5y2+4xy−8x+4y+2021
→A=2x2+4x(y−2)+2(y−2)2+5y2+4y+2020−2(y−2)2→A=2x2+4x(y−2)+2(y−2)2+5y2+4y+2020−2(y−2)2
→A=2(x2+2x(y−2)+(y−2)2)+3y2+12y+2012→A=2(x2+2x(y−2)+(y−2)2)+3y2+12y+2012
→A=2(x+y−2)2+3(y2+4y+4)+2000→A=2(x+y−2)2+3(y2+4y+4)+2000
→A=2(x+y−2)2+3(y+2)2+2000→A=2(x+y−2)2+3(y+2)2+2000
→A≥2⋅0+3⋅0+2000→A≥2⋅0+3⋅0+2000
→A≥2000→A≥2000
Dấu = xảy ra khi {x+y−2=0y+2=0→y=−2,x=4
A=2x2+4y2+4xy+2x+4y+9
=2(x2+x(2y+1)+(2y+1)24)−(2y+1)22+4y2+4y+9
=2(x+2y+12)2−2y2−2y−12+4y2+4y+9
=2(x+2y+12)2+2y2+2y+172
=2(x+2y+12)2+2(y+12)2+8≥8
Dấu '' = '' xảy ra khi: ⇔⎧⎪ ⎪⎨⎪ ⎪⎩y+12=0x+2y+12=0⇔⎧⎨⎩y=−12x=0
Vậy: Min A = 8 khi x=0;y=−12
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