Question

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Answer 1

$a, - \frac{5}{4} + \frac{5}{2} x = - \frac{3}{10} = > \frac{5}{2} x = - \frac{3}{10} + \frac{5}{4} = > \frac{5}{2} x = \frac{19}{20} = > x = \frac{19}{20} : \frac{5}{2} = > x = \frac{19}{50} V ậ y x = \frac{19}{50} b, \frac{4}{3} + \frac{2}{3} : x = \frac{1}{12}, đ k : x \neq 0 = > \frac{2}{3} : x = \frac{1}{12} - \frac{4}{3} = > \frac{2}{3} : x = - \frac{5}{4} = > x = \frac{2}{3} : (- \frac{5}{4}) = > x = \frac{- 8}{15} V ậ y x = - \frac{8}{15} c, (- \frac{1}{4} x - 2) + \frac{3}{4} = \frac{1}{4} = > - \frac{1}{4} x - 2 = \frac{1}{4} - \frac{3}{4} = > \frac{- 1}{4} x - 2 = - \frac{1}{2} = > - \frac{1}{4} x = - \frac{1}{2} + 2 = > - \frac{1}{4} x = \frac{3}{2} = > x = \frac{3}{2} : (- \frac{1}{4}) = > x = - 6 V ậ y x = - 6 d, 3 . |x| - 0, 5 = 1, 2 = > 3 |x| = 1, 2 + 0, 5 = > 3 |x| = 1, 7 = > |x| = \frac{17}{30} = > x = \pm \frac{17}{30} V ậ y x = \pm \frac{17}{30} e, - 2 - 3 |x - 2| = - 8 \frac{1}{3} = > - 3 |x - 2| = - \frac{25}{3} + 2 = > - 3 |x - 2| = - \frac{19}{3} = > |x - 2| = \frac{19}{9} = > x - 2 = \frac{19}{9} h o ặ c x - 2 = - \frac{19}{9} = > x = \frac{19}{9} + 2 h o ặ c x = - \frac{19}{9} + 2 = > x = \frac{37}{9} h o ặ c x = - \frac{1}{9} V ậ y S = \{- \frac{1}{9}; \frac{37}{9}\}$ .

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Answer 2

$a, - \frac{5}{4} + \frac{5}{2} x = - \frac{3}{10} = > \frac{5}{2} x = - \frac{3}{10} + \frac{5}{4} = > \frac{5}{2} x = \frac{19}{20} = > x = \frac{19}{20} : \frac{5}{2} = > x = \frac{19}{50} V ậ y x = \frac{19}{50} b, \frac{4}{3} + \frac{2}{3} : x = \frac{1}{12}, đ k : x \neq 0 = > \frac{2}{3} : x = \frac{1}{12} - \frac{4}{3} = > \frac{2}{3} : x = - \frac{5}{4} = > x = \frac{2}{3} : (- \frac{5}{4}) = > x = \frac{- 8}{15} V ậ y x = - \frac{8}{15} c, (- \frac{1}{4} x - 2) + \frac{3}{4} = \frac{1}{4} = > - \frac{1}{4} x - 2 = \frac{1}{4} - \frac{3}{4} = > \frac{- 1}{4} x - 2 = - \frac{1}{2} = > - \frac{1}{4} x = - \frac{1}{2} + 2 = > - \frac{1}{4} x = \frac{3}{2} = > x = \frac{3}{2} : (- \frac{1}{4}) = > x = - 6 V ậ y x = - 6 d, 3 . |x| - 0, 5 = 1, 2 = > 3 |x| = 1, 2 + 0, 5 = > 3 |x| = 1, 7 = > |x| = \frac{17}{30} = > x = \pm \frac{17}{30} V ậ y x = \pm \frac{17}{30} e, - 2 - 3 |x - 2| = - 8 \frac{1}{3} = > - 3 |x - 2| = - \frac{25}{3} + 2 = > - 3 |x - 2| = - \frac{19}{3} = > |x - 2| = \frac{19}{9} = > x - 2 = \frac{19}{9} h o ặ c x - 2 = - \frac{19}{9} = > x = \frac{19}{9} + 2 h o ặ c x = - \frac{19}{9} + 2 = > x = \frac{37}{9} h o ặ c x = - \frac{1}{9} V ậ y S = \{- \frac{1}{9}; \frac{37}{9}\}$ .

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