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2 câu trả lời 525
\[\begin{array}{l}
a)2.\left| { - 3x - \frac{1}{4}} \right| = \frac{1}{5}\\
= > | - 3x - \frac{1}{4}| = \frac{1}{{10}}\\
= > \left[ \begin{array}{l}
- 3x - \frac{1}{4} = \frac{1}{{10}}\\
- 3x - \frac{1}{4} = \frac{{ - 1}}{{10}}
\end{array} \right.\\
= > \left[ \begin{array}{l}
- 3x = \frac{7}{{20}}\\
- 3x = \frac{3}{{20}}
\end{array} \right.\\
= > \left[ \begin{array}{l}
x = \frac{{ - 7}}{{60}}\\
x = \frac{{ - 1}}{{20}}
\end{array} \right.\\
vay:S = \{ \frac{{ - 7}}{{60}};\frac{{ - 1}}{{20}}\} \\
b)2.\left| {x - 1} \right| - x = 5 + 2x\\
= > 2|x - 1| = 3x + 5\\
+ )x - 1 \ge 0 = > x \ge 1\\
= > 2\left( {x - 1} \right) = 3x + 5\\
= > 2x - 2 = 3x + 5\\
= > 3x - 2x = - 2 - 5\\
= > x = - 7\left( {ktm} \right)\\
+ )x - 1 < 0 = > x < 1\\
= > 2\left( {1 - x} \right) = 3x + 5\\
= > 2 - 2x = 3x + 5\\
= > 3x + 2x = 2 - 5\\
= > 5x = - 3\\
= > x = \frac{{ - 3}}{5}\left( {tm} \right)\\
Vay:x = \frac{{ - 3}}{5}
\end{array}\]
a)2.∣∣−3x−14∣∣=15=>|−3x−14|=110=>[−3x−14=110−3x−14=−110=>[−3x=720−3x=320=>[x=−760x=−120vay:S={−760;−120}b)2.|x−1|−x=5+2x=>2|x−1|=3x+5+)x−1≥0=>x≥1=>2(x−1)=3x+5=>2x−2=3x+5=>3x−2x=−2−5=>x=−7(ktm)+)x−1<0=>x<1=>2(1−x)=3x+5=>2−2x=3x+5=>3x+2x=2−5=>5x=−3=>x=−35(tm)Vay:x=−35
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