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2 câu trả lời 468
\[\begin{array}{l}
a){\left( {x + 2} \right)^3} - {\left( {x + 1} \right)^3}\\
= {x^3} + 6{x^2} + 12x + 8 - ({x^3} + 3{x^2} + 3x + 1)\\
= {x^3} + 6{x^2} + 12x + 8 - {x^3} - 3{x^2} - 3x - 1\\
= 3{x^2} + 9x + 7\\
b){(x + 1)^3} - {\left( {x - 1} \right)^3}\\
{\rm{ = }}{{\rm{x}}^3}{\rm{ + 3}}{{\rm{x}}^2}{\rm{ + 3x + 1 - (}}{{\rm{x}}^3}{\rm{ - 3}}{{\rm{x}}^2}{\rm{ + 3x - 1)}}\\
{\rm{ = }}{{\rm{x}}^3}{\rm{ + 3}}{{\rm{x}}^2}{\rm{ + 3x + 1 - }}{{\rm{x}}^3}{\rm{ + 3}}{{\rm{x}}^2}{\rm{ - 3x + 1}}\\
{\rm{ = 6}}{{\rm{x}}^2}{\rm{ + 2 }}\\
c){\left( {x + 2} \right)^3} - {\left( {x - 1} \right)^3}\\
= {x^3} + 6{x^2} + 12x + 8 - ({x^3} - 3{x^2} + 3x - 1)\\
= {x^3} + 6{x^2} + 12x + 8 - {x^3} + 3{x^2} - 3x + 1\\
= 9{x^2} + 9x + 9\\
d){\left( {x + 2} \right)^3}{\rm{ }} - {\left( {x + 3} \right)^3}\\
= {x^3} + 6{x^2} + 12x + 8 - ({x^3} + 9{x^2} + 27x + 27)\\
= {x^3} + 6{x^2} + 12x + 8 - {x^3} - 9{x^2} - 27x - 27\\
= - 3{x^2} - 15x - 19\\
e){\left( {x + 3} \right)^3} + {\left( {x - 3} \right)^3}\\
= {x^3} + 9{x^2} + 27x + 27 + {x^3} - 9{x^2} + 27x - 27\\
= 2{x^3} + 54x
\end{array}\]
a)(x+2)3−(x+1)3=x3+6x2+12x+8−(x3+3x2+3x+1)=x3+6x2+12x+8−x3−3x2−3x−1=3x2+9x+7b)(x+1)3−(x−1)3=x3+3x2+3x+1−(x3−3x2+3x−1)=x3+3x2+3x+1−x3+3x2−3x+1=6x2+2c)(x+2)3−(x−1)3=x3+6x2+12x+8−(x3−3x2+3x−1)=x3+6x2+12x+8−x3+3x2−3x+1=9x2+9x+9d)(x+2)3−(x+3)3=x3+6x2+12x+8−(x3+9x2+27x+27)=x3+6x2+12x+8−x3−9x2−27x−27=−3x2−15x−19e)(x+3)3+(x−3)3=x3+9x2+27x+27+x3−9x2+27x−27=2x3+54x
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