z¯, z=2+2i, z=-1+2i, lim x→∞fx, C102, y=2x+3x+1, 115, OABC, a22, 35102, 2x.3x2-1=5,22, MAMBd:x-12=y+1-1=z-41, y=2x, y=1-xx, y-0, H, y=23x3-2m+9x2+2m2+9mx+10, fx3;6, S=32V=13Bh, y=fx, V=π53-2ln2, T=a+b, z1-z2, z2-z11+i, 32-434, cos2α=-45S=∫abfxdx, S=π∫abf2xdx, S=1+log325, S=1+ln25, max0;1fx= 6, y=m cos x+1cos x+m y=2sin2 x+3sin 2x-4cos2x, Cn+4n+1-Cn+3n=7n+3A-1;-1;1, y=x3-6x2+9x-2 , (P): 2x-2y+z+5=0, (P), 4z2-4z+3=0 , z1, z2, d1, d2,d3, S=9+99+999+...+99...99⏟n so 9 A1B1C1D1, d1:x+y-1=02x+z=0n⇀=2;-2;1, log2x+1<1, , ∫013x2+1dx, ∫01f''(x)1-xdx=1, y=-x3+3x

z¯, z=2+2i, z=-1+2i, lim x→∞fx, C102, y=2x+3x+1, 115, OABC, a22, 35102, 2x.3x2-...

Ngọc Anh

Đã trả lời bởi chuyên gia

đã hỏi trong Lớp 12 Toán học

· 10:26 29/08/2020

Đã trả lời bởi chuyên gia

$\bar{z}$ , $z = 2 + 2 i$ , $z = - 1 + \sqrt{2} i$ , $\lim_{x \to \infty} f (x)$ , $C_{10}^{2}$ , $y = \frac{2 x + 3}{x + 1}$ , $\frac{11}{5}$ , $O A B C$ , $\frac{a \sqrt{2}}{2}$ , $\frac{3 \sqrt{5}}{10}$ $\sqrt{2}$ , $2^{x} . 3^{x^{2} - 1} = 5$ , $\frac{\sqrt{2}}{2}$ , $\frac{M A}{M B}$ $d : \frac{x - 1}{2} = \frac{y + 1}{- 1} = \frac{z - 4}{1}$ , $y = 2 x, y = \frac{1 - x}{x}, y - 0$ , $(H)$ , $y = \frac{2}{3} x^{3} - (2 m + 9) x^{2} + 2 (m^{2} + 9 m) x + 10$ , $f (x)$

$(3; 6)$ , $S = \frac{\sqrt{3}}{2}$

$V = \frac{1}{3} B h$ , $y = f (x)$ , $V = π (\frac{5}{3} - 2 \ln 2)$ , $T = a + b$ , $|z_{1} - z_{2}|$ , $\frac{z_{2} - z_{1}}{1 + i}$ , $\frac{3 (2 - \sqrt[3]{4})}{4}$ , $\cos 2 α = - \frac{4}{5}$

$S = \int_{a}^{b} f (x) d x$ , $S = π \int_{a}^{b} f^{2} (x) d x$ , $S = 1 + \log_{3} \frac{2}{5}$ , $S = 1 + \ln \frac{2}{5}$ , $\max_{[0; 1]} |f (x)| = 6$ , $y = \frac{m \cos x + 1}{\cos x + m}$

$y = 2 \sin^{2} x + 3 \sin 2 x - 4 \cos^{2} x$ , $C_{n + 4}^{n + 1} - C_{n + 3}^{n} = 7 (n + 3)$

$A (- 1; - 1; 1)$ , $y = x^{3} - 6 x^{2} + 9 x - 2$ , $(P) : 2 x - 2 y + z + 5 = 0$ , $(P)$ , $4 z^{2} - 4 z + 3 = 0$ , $z_{1}, z_{2}$ , $d_{1}, d_{2}, d_{3}$ , $S = 9 + 99 + 999 + . . . + \underset{n so 9}{\underset{⏟}{99 . . . 99}}$

$A_{1} B_{1} C_{1} D_{1}$ , $(d_{1}) : \{\begin{cases} x + y - 1 = 0 \\ 2 x + z = 0 \end{cases}$

$\overset{⇀}{n} = (2; - 2; 1)$ , $\log_{2} (x + 1) < 1$ , , $\int_{0}^{1} (3 x^{2} + 1) d x$ , $\int_{0}^{1} f'' (x) (1 - x) d x = 1$ , $y = - {|x|}^{3} + 3 |x|$

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Phương Anh

6 năm trước

$A B C D . A' B' C' D'$ , $V = 9 {πa}^{3}$ , $9^{x} + 3^{x + 1} < 0$ , $t = 3^{x}$

$y = f (x)$ , $ℝ$ , $f (x) = \sin x + 1$ , $x \in [0; 1]$ , $\frac{10!}{3!}$ , $60^{°}$ , $\frac{\sqrt{3}}{2} a^{3}$ $(- \infty; - 1) \cup (2; + \infty)$ , $45^{°}$ , $π$ , $\hat{B A D} = 60^{°}$