Question

Đã trả lời bởi chuyên gia

Answer 1

${\mathop{\rm BTNT}\nolimits} ({\rm{N}})$ ta có ${{\rm{n}}_{{\rm{N}}{{\rm{H}}_3}}} = {{\rm{n}}_{{\rm{HN}}{{\rm{O}}_3}}} = 2\,\,(\;{\rm{mol}})$

$\begin{array}{l} 4 {NH}_{3} + 5 O_{2} \overset{P t, t^{°}}{\to} 4 NO + 6 H_{2} O \\ 2 \to 2, 5 2 m o l \end{array}$

$\begin{array}{l}2{\rm{NO}} + {{\rm{O}}_2} \to 2{\rm{N}}{{\rm{O}}_2}\\2\,\,\,\,\, \to \,\,\,\,1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,mol\end{array}$

$\begin{array}{l}4{\rm{N}}{{\rm{O}}_2} + {{\rm{O}}_2} + 2{{\rm{H}}_2}{\rm{O}} \to 4{\rm{HN}}{{\rm{O}}_3}\\2\,\,\,\, \to \,\,\,\,\,0,5\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,mol\end{array}$

${n_{{O_2}}}$ban đầu = a – 2 (mol)

$Quy trình sản xuất ${\rm{HN}}{{\rm{O}}_3}$ trong công nghiệp từ nguyên liệu ${\rm{N}}{{\rm{H}}_3}$ được thực hiện như sau: (ảnh 1)$

Chọn C.

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Answer 2