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2 câu trả lời 237
The equation you've provided is:
\[ \frac{4}{x} + \frac{2}{y} = 1 \]
To solve this equation for \( x \) and \( y \), we can follow these steps:
1. **Identify the equation:**
\[ \frac{4}{x} + \frac{2}{y} = 1 \]
2. **Multiply through by \( xy \) to eliminate fractions:**
\[ 4y + 2x = xy \]
3. **Rearrange terms to bring all terms involving \( x \) and \( y \) on one side:**
\[ xy - 2x - 4y = 0 \]
4. **Factor out \( x \) from the terms involving \( x \):**
\[ x(y - 2) = 4y \]
5. **Solve for \( x \):**
\[ x = \frac{4y}{y - 2} \]
Now, the equation is solved for \( x \) in terms of \( y \). Similarly, you could solve for \( y \) in terms of \( x \):
\[ \frac{4}{x} + \frac{2}{y} = 1 \]
\[ 4y + 2x = xy \]
\[ xy - 2x - 4y = 0 \]
\[ y(x - 2) = 2x \
<=> 2x +4y = xy
<=> x(y-2) = 4y . Vì y = 2 không là nghiệm nên
x= 4y/(y-2) = 4 + 8/(y-2)
vì x nguyên nên 8 chia hết y-2
vậy y-2 = 8 => y = 10 => x = 5
vậy y-2 = -8 => y = -6 => x = 3
vậy y-2 = 4 => y = 6 => x = 6
vậy y-2 = -4 => y = -2 => x = 2
vậy y-2 = 2 => y = 4 => x = 8
vậy y-2 = -2 => y = 0 (loại)
vậy y-2 = 1 => y = 3 => x = 12
vậy y-2 = -1 => y = 1 => x = -4
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