Question

Đã trả lời bởi chuyên gia

Answer 1

Ta có:

$\frac{9}{20} = \frac{9}{4.5} = \frac{5 + 4}{4.5} = \frac{5}{4.5} + \frac{4}{4.5} = \frac{1}{4} + \frac{1}{5}$

$\frac{11}{30} = \frac{11}{5.6} = \frac{6 + 5}{5.6} = \frac{6}{5.6} + \frac{5}{5.6} = \frac{1}{5} + \frac{1}{6}$

$\frac{13}{42} = \frac{13}{6.7} = \frac{7 + 6}{6.7} = \frac{7}{6.7} + \frac{6}{6.7} = \frac{1}{6} + \frac{1}{7}$

…

$\frac{197}{9702} = \frac{197}{98.99} = \frac{99 + 98}{98.99} = \frac{99}{98.99} + \frac{98}{98.99} = \frac{1}{98} + \frac{1}{99}$

$\frac{199}{9900} = \frac{199}{99.100} = \frac{100 + 99}{99.100} = \frac{100}{99.100} + \frac{99}{99.100} = \frac{1}{99} + \frac{1}{100}$

Do đó $H = \frac{38}{50} + \frac{9}{20} - \frac{11}{30} + \frac{13}{42} - \frac{15}{56} + \frac{17}{72} - ... + \frac{197}{9702} - \frac{199}{9900}$

$= \frac{38}{50} + (\frac{1}{4} + \frac{1}{5}) - (\frac{1}{5} + \frac{1}{6}) + (\frac{1}{6} + \frac{1}{7}) - (\frac{1}{7} + \frac{1}{8}) + + (\frac{1}{8} + \frac{1}{9}) - ... + (\frac{1}{98} + \frac{1}{99}) - (\frac{1}{99} + \frac{1}{100}) = \frac{38}{50} + \frac{1}{4} + \frac{1}{5} - \frac{1}{5} - \frac{1}{6} + \frac{1}{6} + \frac{1}{7} - \frac{1}{7} - \frac{1}{8} + \frac{1}{8} + \frac{1}{9} = \frac{38}{50} + \frac{1}{4} + (\frac{1}{5} - \frac{1}{5}) + (- \frac{1}{6} + \frac{1}{6}) + (\frac{1}{7} - \frac{1}{7}) + (- \frac{1}{8} + \frac{1}{8}) + (\frac{1}{9} - \frac{1}{9}) + ... + (- \frac{1}{98} + \frac{1}{98}) + (\frac{1}{99} - \frac{1}{99}) - \frac{1}{100} = \frac{38}{50} + \frac{1}{4} + 0 + 0 + 0 + 0 + 0 + ... + 0 + 0 - \frac{1}{100} = \frac{38}{50} + \frac{1}{4} - \frac{1}{100} = \frac{76}{100} + \frac{25}{100} - \frac{1}{100} = \frac{76 + 25 - 1}{100} = \frac{100}{100}$

= 1.

Vậy H = 1.

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Answer 2

Ta có:

$\frac{9}{20} = \frac{9}{4.5} = \frac{5 + 4}{4.5} = \frac{5}{4.5} + \frac{4}{4.5} = \frac{1}{4} + \frac{1}{5}$

$\frac{11}{30} = \frac{11}{5.6} = \frac{6 + 5}{5.6} = \frac{6}{5.6} + \frac{5}{5.6} = \frac{1}{5} + \frac{1}{6}$

$\frac{13}{42} = \frac{13}{6.7} = \frac{7 + 6}{6.7} = \frac{7}{6.7} + \frac{6}{6.7} = \frac{1}{6} + \frac{1}{7}$

…

$\frac{197}{9702} = \frac{197}{98.99} = \frac{99 + 98}{98.99} = \frac{99}{98.99} + \frac{98}{98.99} = \frac{1}{98} + \frac{1}{99}$

$\frac{199}{9900} = \frac{199}{99.100} = \frac{100 + 99}{99.100} = \frac{100}{99.100} + \frac{99}{99.100} = \frac{1}{99} + \frac{1}{100}$

Do đó $H = \frac{38}{50} + \frac{9}{20} - \frac{11}{30} + \frac{13}{42} - \frac{15}{56} + \frac{17}{72} - ... + \frac{197}{9702} - \frac{199}{9900}$

$= \frac{38}{50} + (\frac{1}{4} + \frac{1}{5}) - (\frac{1}{5} + \frac{1}{6}) + (\frac{1}{6} + \frac{1}{7}) - (\frac{1}{7} + \frac{1}{8}) + + (\frac{1}{8} + \frac{1}{9}) - ... + (\frac{1}{98} + \frac{1}{99}) - (\frac{1}{99} + \frac{1}{100}) = \frac{38}{50} + \frac{1}{4} + \frac{1}{5} - \frac{1}{5} - \frac{1}{6} + \frac{1}{6} + \frac{1}{7} - \frac{1}{7} - \frac{1}{8} + \frac{1}{8} + \frac{1}{9} = \frac{38}{50} + \frac{1}{4} + (\frac{1}{5} - \frac{1}{5}) + (- \frac{1}{6} + \frac{1}{6}) + (\frac{1}{7} - \frac{1}{7}) + (- \frac{1}{8} + \frac{1}{8}) + (\frac{1}{9} - \frac{1}{9}) + ... + (- \frac{1}{98} + \frac{1}{98}) + (\frac{1}{99} - \frac{1}{99}) - \frac{1}{100} = \frac{38}{50} + \frac{1}{4} + 0 + 0 + 0 + 0 + 0 + ... + 0 + 0 - \frac{1}{100} = \frac{38}{50} + \frac{1}{4} - \frac{1}{100} = \frac{76}{100} + \frac{25}{100} - \frac{1}{100} = \frac{76 + 25 - 1}{100} = \frac{100}{100}$

= 1.

Vậy H = 1.

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