Question

Đã trả lời bởi chuyên gia

Answer 1

Bài làm.

${(- \frac{2}{3})}^{2} : (\frac{7}{18} + \frac{2}{9} - \frac{1}{2}) = \frac{4}{9} : \frac{7 + 4 - 9}{18} = \frac{4}{9} . \frac{18}{2} = 4$

${(\frac{1}{2} - \frac{1}{6})}^{10} : {(\frac{1}{3})}^{8} = {(\frac{1}{3})}^{10} : {(\frac{1}{3})}^{8} = {(\frac{1}{3})}^{2}$

${(\frac{6}{5})}^{2013} . {(\frac{5}{6})}^{2013} + {(\frac{2012}{2013})}^{0} = 1 + 1 = 2$

${(\frac{2}{3} - \frac{1}{2})}^{2} : \frac{15}{6} + {(\frac{51}{15})}^{0} = \frac{13}{6} . \frac{6}{15} + 1 = \frac{1}{90} + 1 = \frac{91}{90}$

$- {(\frac{2}{7})}^{2} . 343 - [- {(\frac{2013}{2014})}^{0} + 64 . {(\frac{1}{2})}^{3}] = - 28 + 1 - 8 = - 35$

...Xem thêm

Answer 2

Bài làm.

${(- \frac{2}{3})}^{2} : (\frac{7}{18} + \frac{2}{9} - \frac{1}{2}) = \frac{4}{9} : \frac{7 + 4 - 9}{18} = \frac{4}{9} . \frac{18}{2} = 4$

${(\frac{1}{2} - \frac{1}{6})}^{10} : {(\frac{1}{3})}^{8} = {(\frac{1}{3})}^{10} : {(\frac{1}{3})}^{8} = {(\frac{1}{3})}^{2}$

${(\frac{6}{5})}^{2013} . {(\frac{5}{6})}^{2013} + {(\frac{2012}{2013})}^{0} = 1 + 1 = 2$

${(\frac{2}{3} - \frac{1}{2})}^{2} : \frac{15}{6} + {(\frac{51}{15})}^{0} = \frac{13}{6} . \frac{6}{15} + 1 = \frac{1}{90} + 1 = \frac{91}{90}$

$- {(\frac{2}{7})}^{2} . 343 - [- {(\frac{2013}{2014})}^{0} + 64 . {(\frac{1}{2})}^{3}] = - 28 + 1 - 8 = - 35$

Answer 3

1)

${(\frac{- 2}{3})}^{2} \div (\frac{7}{18} + \frac{2}{9} - \frac{1}{2}) = \frac{4}{9} \div (\frac{7}{18} + \frac{4}{18} - \frac{9}{18}) = \frac{4}{9} \div \frac{2}{18} = \frac{4}{9} \times \frac{18}{2} = \frac{4 \times 2 \times 9}{9 \times 2} = 4 2) {(\frac{1}{2} - \frac{1}{6})}^{10} \div {(\frac{1}{3})}^{8} = {(\frac{3}{6} - \frac{1}{6})}^{10} \div {(\frac{1}{3})}^{8} = {(\frac{2}{6})}^{10} \div {(\frac{1}{3})}^{8} = {(\frac{1}{3})}^{10} \div {(\frac{1}{3})}^{8} = {(\frac{1}{3})}^{2} = \frac{1}{9} 3) {(\frac{6}{5})}^{2013} . {(\frac{5}{6})}^{2013} + {(\frac{2012}{2013})}^{0} = {(\frac{6}{5} . \frac{5}{6})}^{2013} + 1 = 1^{2013} + 1 = 1 + 1 = 2 4) {(\frac{2}{3} - \frac{1}{2})}^{2} \div \frac{15}{6} + {(\frac{51}{15})}^{0} = {(\frac{4}{6} - \frac{3}{6})}^{2} \times \frac{6}{15} + 1 = {(\frac{1}{6})}^{2} \times \frac{6}{15} + 1 = \frac{1}{6 \times 15} + 1 = \frac{1}{80} + \frac{80}{80} = \frac{81}{80} 5) - {(\frac{2}{7})}^{2} . 343 - [- {(\frac{2013}{2014})}^{0} + 64 . {(\frac{1}{2})}^{3}] = \frac{- 2^{2}}{7^{2}} . 7^{3} - (- 1 + 2^{6} . \frac{1}{2^{3}}) = - 4.7 - (- 1 + 2^{3}) = - 28 - (- 1 + 8) = - 28 - 7 = - 35$

...Xem thêm

Answer 4

1)

${(\frac{- 2}{3})}^{2} \div (\frac{7}{18} + \frac{2}{9} - \frac{1}{2}) = \frac{4}{9} \div (\frac{7}{18} + \frac{4}{18} - \frac{9}{18}) = \frac{4}{9} \div \frac{2}{18} = \frac{4}{9} \times \frac{18}{2} = \frac{4 \times 2 \times 9}{9 \times 2} = 4 2) {(\frac{1}{2} - \frac{1}{6})}^{10} \div {(\frac{1}{3})}^{8} = {(\frac{3}{6} - \frac{1}{6})}^{10} \div {(\frac{1}{3})}^{8} = {(\frac{2}{6})}^{10} \div {(\frac{1}{3})}^{8} = {(\frac{1}{3})}^{10} \div {(\frac{1}{3})}^{8} = {(\frac{1}{3})}^{2} = \frac{1}{9} 3) {(\frac{6}{5})}^{2013} . {(\frac{5}{6})}^{2013} + {(\frac{2012}{2013})}^{0} = {(\frac{6}{5} . \frac{5}{6})}^{2013} + 1 = 1^{2013} + 1 = 1 + 1 = 2 4) {(\frac{2}{3} - \frac{1}{2})}^{2} \div \frac{15}{6} + {(\frac{51}{15})}^{0} = {(\frac{4}{6} - \frac{3}{6})}^{2} \times \frac{6}{15} + 1 = {(\frac{1}{6})}^{2} \times \frac{6}{15} + 1 = \frac{1}{6 \times 15} + 1 = \frac{1}{80} + \frac{80}{80} = \frac{81}{80} 5) - {(\frac{2}{7})}^{2} . 343 - [- {(\frac{2013}{2014})}^{0} + 64 . {(\frac{1}{2})}^{3}] = \frac{- 2^{2}}{7^{2}} . 7^{3} - (- 1 + 2^{6} . \frac{1}{2^{3}}) = - 4.7 - (- 1 + 2^{3}) = - 28 - (- 1 + 8) = - 28 - 7 = - 35$

2 câu trả lời 348

Câu hỏi hot cùng chủ đề

Bài viết mới nhất Lớp 7