Question

Đã trả lời bởi chuyên gia

Answer 1

Ta có:

$a) (x - 1) - x (- x + 2) = x - 1 + x^{2} - 2 x = x^{2} - x - 1 b) - x (- x + 2) - x (x + 3) = - x . (- x + 2 + x + 3) = - 5 x c) - 2 x (x + 1) + 3 x (- 2 x - 1) = - 2 x^{2} - 2 x - 6 x^{2} - 3 x = - 8 x^{2} - 5 x = - x . (8 x + 5) d) - 4 x (x + 5) - x (x + 6) = - x . (4 x + 20) - x (x + 6) = - x (4 x + 20 + x + 6) = - x . (5 x + 26) e) (x - 2) . (x + 1) + (x + 3) . (- x - 2) = x^{2} - 2 x + x - 2 - x^{2} - 3 x - 2 x - 6 = - 6 x - 8 = - 2 . (3 x + 4) f) (x - 3) . (- x + 5) - (- x + 4) . (x - 6) = - x^{2} + 3 x + 5 x - 15 + x^{2} - 4 x - 6 x + 24 = - 2 x + 9 g) (- x - 6) . (x + 1) - (- x + 3) . (x - 2) = - x^{2} - 6 x - x - 6 + x^{2} - 3 x - 2 x + 6 = - 12 x h) (x^{2} - x y + y^{2}) . (- x y) + x y . (x^{2} - x y + 2 y^{2}) = x y . (- x^{2} + x y - y^{2} + x^{2} - x y + 2 y^{2}) = x y . y^{2} = x y^{3}$

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Answer 2

Ta có:

$a) (x - 1) - x (- x + 2) = x - 1 + x^{2} - 2 x = x^{2} - x - 1 b) - x (- x + 2) - x (x + 3) = - x . (- x + 2 + x + 3) = - 5 x c) - 2 x (x + 1) + 3 x (- 2 x - 1) = - 2 x^{2} - 2 x - 6 x^{2} - 3 x = - 8 x^{2} - 5 x = - x . (8 x + 5) d) - 4 x (x + 5) - x (x + 6) = - x . (4 x + 20) - x (x + 6) = - x (4 x + 20 + x + 6) = - x . (5 x + 26) e) (x - 2) . (x + 1) + (x + 3) . (- x - 2) = x^{2} - 2 x + x - 2 - x^{2} - 3 x - 2 x - 6 = - 6 x - 8 = - 2 . (3 x + 4) f) (x - 3) . (- x + 5) - (- x + 4) . (x - 6) = - x^{2} + 3 x + 5 x - 15 + x^{2} - 4 x - 6 x + 24 = - 2 x + 9 g) (- x - 6) . (x + 1) - (- x + 3) . (x - 2) = - x^{2} - 6 x - x - 6 + x^{2} - 3 x - 2 x + 6 = - 12 x h) (x^{2} - x y + y^{2}) . (- x y) + x y . (x^{2} - x y + 2 y^{2}) = x y . (- x^{2} + x y - y^{2} + x^{2} - x y + 2 y^{2}) = x y . y^{2} = x y^{3}$

Answer 3

... $1) x - 1 + x^{2} - 2 x = x^{2} - x - 1 2) x^{2} - 2 x - x^{2} - 3 x = - 5 x 3) - 2 x^{2} - 2 x - 6 x^{2} - 3 x = - 8 x^{2} - 5 x 4) - 4 x^{2} - 20 x - x^{2} - 6 x = - 5 x^{2} - 26 x 5) (x^{2} - 2 x + x - 2) + (- x^{2} - 2 x - 3 x - 6) = - 6 x - 8 6) (- x^{2} + 5 x + 3 x - 15) - (- x^{2} + 6 x + 4 x - 24) = - x^{2} + 8 x - 15 + x^{2} - 10 x + 24 = - 2 x + 9 7) (- x^{2} - x - 6 x - 6) - (- x^{2} + 2 x + 3 x - 6) = - x^{2} - 7 x - 6 + x^{2} - 5 x + 6 = - 12 x 8) (- x^{3} y + x^{2} y^{2} - x y^{3}) + (x^{3} y - x^{2} y^{2} + 2 x y^{3}) = x y^{3}$

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Answer 4

... $1) x - 1 + x^{2} - 2 x = x^{2} - x - 1 2) x^{2} - 2 x - x^{2} - 3 x = - 5 x 3) - 2 x^{2} - 2 x - 6 x^{2} - 3 x = - 8 x^{2} - 5 x 4) - 4 x^{2} - 20 x - x^{2} - 6 x = - 5 x^{2} - 26 x 5) (x^{2} - 2 x + x - 2) + (- x^{2} - 2 x - 3 x - 6) = - 6 x - 8 6) (- x^{2} + 5 x + 3 x - 15) - (- x^{2} + 6 x + 4 x - 24) = - x^{2} + 8 x - 15 + x^{2} - 10 x + 24 = - 2 x + 9 7) (- x^{2} - x - 6 x - 6) - (- x^{2} + 2 x + 3 x - 6) = - x^{2} - 7 x - 6 + x^{2} - 5 x + 6 = - 12 x 8) (- x^{3} y + x^{2} y^{2} - x y^{3}) + (x^{3} y - x^{2} y^{2} + 2 x y^{3}) = x y^{3}$

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