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1 câu trả lời 3926
a) $2\cos x-3\cos \left( \pi -x \right)+5\sin \left( \dfrac{7\pi }{2}-x \right)+\cot \left( \dfrac{3\pi }{2}-x \right)$
$=2\cos x+3\cos \left( -x \right)+5\sin \left( \dfrac{7\pi }{2}-4\pi -x \right)+\cot \left( \pi +\dfrac{\pi }{2}-x \right)$
$=2\cos x+3\cos x+5\sin \left( \dfrac{-\pi }{2}-x \right)+\cot \left( \dfrac{\pi }{2}-x \right)$
$=5\cos x-5\sin \left( \dfrac{\pi }{2}+x \right)+\tan x$
$=5\cos x-5\sin \left[ \dfrac{\pi }{2}-\left( -x \right) \right]+\tan x$
$=5\cos x-5\cos \left( -x \right)+\tan x$
$=5\cos x-5\cos x+\tan x$
$=\tan x$
b)$\sin \left( x-17\pi \right).\cos \left( x+\pi \right).\tan \left( \dfrac{3\pi }{2}-x \right)$
$=\sin \left( x-\pi -16\pi \right).\left( -\cos x \right).\tan \left( \pi +\dfrac{\pi }{2}-x \right)$
$=\sin \left( x-\pi \right).\left( -\cos x \right).\tan \left( \dfrac{\pi }{2}-x \right)$
$=-\sin x.\left( -\cos x \right).\cot x$
$=\sin x.\cos x.\dfrac{\cos x}{\sin x}$
$={{\cos }^{2}}x$
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