Cho tam giác ABC vuông tại A có AB <AC, đường cao AH. Trên tia HC lấy D sao cho HD=HB .kẻ CE vuông góc với AD tại E. Đường thẳng CE cắt đường thẳng AH tại F.chứng minh FD vuông góc với Ac.tính số đó góc ACB
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2 câu trả lời 1049

a. Xét tam giác AFC có CH và AE là 2 đường cao cắt nhau tại D
D là trực tâm của tam giác AFC
do đó
Phần a: Chứng minh FD⟂ACcap F cap D ⟂ cap A cap C
??⟂??
Bước 1: Chứng minh △AHB≅△AHDtriangle cap A cap H cap B is congruent to triangle cap A cap H cap D
△???≅△???
Ta có HB = HD (gt), \angle AHB = \angle AHD = 90^\circ, AH là cạnh chung, Vậy \triangle AHB \cong \triangle AHD (c.g.c).
Bước 2: Chứng minh ∠ACB=∠HACangle cap A cap C cap B equals angle cap H cap A cap C
∠???=∠???
Vì △AHB≅△AHDtriangle cap A cap H cap B is congruent to triangle cap A cap H cap D
△???≅△???
nên ∠HAB=∠HADangle cap H cap A cap B equals angle cap H cap A cap D
∠???=∠???
.
Trong tam giác ABCcap A cap B cap C
???
, ta có ∠HAB+∠ACB=90∘angle cap H cap A cap B plus angle cap A cap C cap B equals 90 raised to the exponent composed with end-exponent
∠???+∠???=90∘
.
Vì ∠HAD=∠HABangle cap H cap A cap D equals angle cap H cap A cap B
∠???=∠???
, ta có ∠ACB=∠HACangle cap A cap C cap B equals angle cap H cap A cap C
∠???=∠???
.
Bước 3: Chứng minh ∠AFD=90∘angle cap A cap F cap D equals 90 raised to the exponent composed with end-exponent
∠???=90∘
Ta có ∠AFE=90∘angle cap A cap F cap E equals 90 raised to the exponent composed with end-exponent
∠???=90∘
(vì CE⟂ADcap C cap E ⟂ cap A cap D
??⟂??
tại Ecap E
?
).
∠AFD=90∘−∠CAF=90∘−∠ACBangle cap A cap F cap D equals 90 raised to the exponent composed with end-exponent minus angle cap C cap A cap F equals 90 raised to the exponent composed with end-exponent minus angle cap A cap C cap B
∠???=90∘−∠???=90∘−∠???
.
Mà ∠ACB=∠HACangle cap A cap C cap B equals angle cap H cap A cap C
∠???=∠???
, nên ∠AFD=90∘−∠HACangle cap A cap F cap D equals 90 raised to the exponent composed with end-exponent minus angle cap H cap A cap C
∠???=90∘−∠???
.
Trong tam giác AFCcap A cap F cap C
???
, ta có ∠AFC+∠CAF+∠ACF=180∘angle cap A cap F cap C plus angle cap C cap A cap F plus angle cap A cap C cap F equals 180 raised to the exponent composed with end-exponent
∠???+∠???+∠???=180∘
.
∠AFC=180∘−∠CAF−∠ACF=180∘−∠HAC−∠ACFangle cap A cap F cap C equals 180 raised to the exponent composed with end-exponent minus angle cap C cap A cap F minus angle cap A cap C cap F equals 180 raised to the exponent composed with end-exponent minus angle cap H cap A cap C minus angle cap A cap C cap F
∠???=180∘−∠???−∠???=180∘−∠???−∠???
.
∠AFD=90∘angle cap A cap F cap D equals 90 raised to the exponent composed with end-exponent
∠???=90∘
, nên FD⟂ACcap F cap D ⟂ cap A cap C
??⟂??
.
Phần b: Tính số đo góc ACB Ta có AH \perp BC, \angle ACB = \angle HAC, \angle HAB + \angle HAC = 90^\circ, \angle ACB = \angle HAC = 30^\circ.
Vậy ∠ACB=30∘angle cap A cap C cap B equals 30 raised to the exponent composed with end-exponent
∠???=30∘
.
??⟂??
Bước 1: Chứng minh △AHB≅△AHDtriangle cap A cap H cap B is congruent to triangle cap A cap H cap D
△???≅△???
Ta có HB = HD (gt), \angle AHB = \angle AHD = 90^\circ, AH là cạnh chung, Vậy \triangle AHB \cong \triangle AHD (c.g.c).
Bước 2: Chứng minh ∠ACB=∠HACangle cap A cap C cap B equals angle cap H cap A cap C
∠???=∠???
Vì △AHB≅△AHDtriangle cap A cap H cap B is congruent to triangle cap A cap H cap D
△???≅△???
nên ∠HAB=∠HADangle cap H cap A cap B equals angle cap H cap A cap D
∠???=∠???
.
Trong tam giác ABCcap A cap B cap C
???
, ta có ∠HAB+∠ACB=90∘angle cap H cap A cap B plus angle cap A cap C cap B equals 90 raised to the exponent composed with end-exponent
∠???+∠???=90∘
.
Vì ∠HAD=∠HABangle cap H cap A cap D equals angle cap H cap A cap B
∠???=∠???
, ta có ∠ACB=∠HACangle cap A cap C cap B equals angle cap H cap A cap C
∠???=∠???
.
Bước 3: Chứng minh ∠AFD=90∘angle cap A cap F cap D equals 90 raised to the exponent composed with end-exponent
∠???=90∘
Ta có ∠AFE=90∘angle cap A cap F cap E equals 90 raised to the exponent composed with end-exponent
∠???=90∘
(vì CE⟂ADcap C cap E ⟂ cap A cap D
??⟂??
tại Ecap E
?
).
∠AFD=90∘−∠CAF=90∘−∠ACBangle cap A cap F cap D equals 90 raised to the exponent composed with end-exponent minus angle cap C cap A cap F equals 90 raised to the exponent composed with end-exponent minus angle cap A cap C cap B
∠???=90∘−∠???=90∘−∠???
.
Mà ∠ACB=∠HACangle cap A cap C cap B equals angle cap H cap A cap C
∠???=∠???
, nên ∠AFD=90∘−∠HACangle cap A cap F cap D equals 90 raised to the exponent composed with end-exponent minus angle cap H cap A cap C
∠???=90∘−∠???
.
Trong tam giác AFCcap A cap F cap C
???
, ta có ∠AFC+∠CAF+∠ACF=180∘angle cap A cap F cap C plus angle cap C cap A cap F plus angle cap A cap C cap F equals 180 raised to the exponent composed with end-exponent
∠???+∠???+∠???=180∘
.
∠AFC=180∘−∠CAF−∠ACF=180∘−∠HAC−∠ACFangle cap A cap F cap C equals 180 raised to the exponent composed with end-exponent minus angle cap C cap A cap F minus angle cap A cap C cap F equals 180 raised to the exponent composed with end-exponent minus angle cap H cap A cap C minus angle cap A cap C cap F
∠???=180∘−∠???−∠???=180∘−∠???−∠???
.
∠AFD=90∘angle cap A cap F cap D equals 90 raised to the exponent composed with end-exponent
∠???=90∘
, nên FD⟂ACcap F cap D ⟂ cap A cap C
??⟂??
.
Phần b: Tính số đo góc ACB Ta có AH \perp BC, \angle ACB = \angle HAC, \angle HAB + \angle HAC = 90^\circ, \angle ACB = \angle HAC = 30^\circ.
Vậy ∠ACB=30∘angle cap A cap C cap B equals 30 raised to the exponent composed with end-exponent
∠???=30∘
.
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