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1 câu trả lời 14
Để A Ç B ¹ Æ thì \[\left\{ \begin{array}{l}\left[ \begin{array}{l}m - 1 < - 3\\\frac{{m + 3}}{2} \ge 3\end{array} \right.\\m - 1 \le \frac{{m + 3}}{2}\end{array} \right. \Leftrightarrow \left\{ \begin{array}{l}\left[ \begin{array}{l}m < - 2\\m \ge 3\end{array} \right.\\m \le 5\end{array} \right.\]
\[ \Leftrightarrow \left[ \begin{array}{l}\left\{ \begin{array}{l}m < - 2\\m \le 5\end{array} \right.\\\left\{ \begin{array}{l}m \ge 3\\m \le 5\end{array} \right.\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}m < - 2\\3 \le m \le 5\end{array} \right.\]
Vậy \[m \in \left\{ { - \infty ; - 2} \right\} \cup {\rm{[}}3;5]\].
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