Question

Đã trả lời bởi chuyên gia

Answer 1

a) $- \frac{3}{5} x = \frac{12}{25}$

$x = \frac{12}{25} : (- \frac{3}{5})$

$x = \frac{12}{25} . \frac{- 5}{3}$

$x = \frac{- 4}{5}$

Vậy $x = \frac{- 4}{5}$

b) $\frac{3}{5} x - \frac{3}{4} = - 1 \frac{1}{2}$

$\frac{3}{5} x - \frac{3}{4} = \frac{- 3}{2}$

$\frac{3}{5} x = \frac{- 3}{2} + \frac{3}{4}$

$\frac{3}{5} x = \frac{- 6}{4} + \frac{3}{4}$

$\frac{3}{5} x = \frac{- 3}{4}$

$x = \frac{- 3}{4} : \frac{3}{5}$

$x = \frac{- 3}{4} . \frac{5}{3}$

$x = \frac{- 5}{4}$

Vậy $x = \frac{- 5}{4}$

c) $\frac{2}{5} + \frac{3}{5} : x = 0, 5$

$\frac{2}{5} + \frac{3}{5} : x = \frac{1}{2}$

$\frac{3}{5} : x = \frac{1}{2} - \frac{2}{5}$

$\frac{3}{5} : x = \frac{5}{10} - \frac{4}{10}$

$\frac{3}{5} : x = \frac{1}{10}$

$x = \frac{3}{5} : \frac{1}{10}$

$x = \frac{3}{5} . \frac{10}{1}$

x = 6

Vậy x = 6

d) $\frac{3}{4} - (x - \frac{1}{2}) = 1 \frac{2}{3}$

$\frac{3}{4} - (x - \frac{1}{2}) = \frac{5}{3}$

$x - \frac{1}{2} = \frac{3}{4} - \frac{5}{3} x - \frac{1}{2} = \frac{9}{12} - \frac{20}{12} x - \frac{1}{2} = \frac{- 11}{12} x = \frac{- 11}{12} + \frac{1}{2} x = \frac{- 11}{12} + \frac{6}{12} x = \frac{- 5}{12}$

Vậy $x = \frac{- 5}{12}$

e) $2 \frac{2}{15} : (\frac{1}{3} - 5 x) = - 2 \frac{2}{5}$

$\frac{32}{15} : (\frac{1}{3} - 5 x) = \frac{- 12}{5} \frac{1}{3} - 5 x = \frac{32}{15} : \frac{- 12}{5} \frac{1}{3} - 5 x = \frac{32}{15} . \frac{5}{- 12} \frac{1}{3} - 5 x = \frac{- 8}{9} 5 x = \frac{1}{3} - \frac{- 8}{9} 5 x = \frac{3}{9} + \frac{8}{9} 5 x = \frac{11}{9} x = \frac{11}{9} : 5 x = \frac{11}{45}$

Vậy $x = \frac{11}{45}$

g) $x^{2} + \frac{1}{9} = \frac{5}{3} : 3$

$x^{2} + \frac{1}{9} = \frac{5}{9} x^{2} = \frac{5}{9} - \frac{1}{9} x^{2} = \frac{4}{9} x^{2} = \frac{4}{9} x^{2} = {(\frac{2}{3})}^{2} = {(\frac{- 2}{3})}^{2} +) x = \frac{- 2}{3} +) x = \frac{2}{3} V ậ y x = \frac{2}{3} h o ặ c x = \frac{- 2}{3}$

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Answer 2