Question

Đã trả lời bởi chuyên gia

Answer 1

\[\begin{array}{l}
1,{x^4} + {x^3} - 8x - 8\\
= {x^3}\left( {x + 1} \right) - 8\left( {x + 1} \right)\\
= \left( {x + 1} \right)\left( {{x^3} - 8} \right)\\
= \left( {x + 1} \right)\left( {x - 2} \right)\left( {{x^2} + 2x + 4} \right)\\
2,{x^2} + xy - x - y\\
= x\left( {x + y} \right) - \left( {x + y} \right)\\
= \left( {x + y} \right)\left( {x - 1} \right)\\
3,xy + 1 - {x^2} + y\\
= \left( {xy + y} \right) - \left( {{x^2} - 1} \right)\\
= y\left( {x + 1} \right) - \left( {x + 1} \right)\left( {x - 1} \right)\\
= \left( {x + 1} \right)\left( {y - x + 1} \right)\\
4,xy + 2y - 3(x + 2)\\
= y\left( {x + 2} \right) - 3\left( {x + 2} \right)\\
= \left( {x + 2} \right)\left( {y - 3} \right)\\
5,3(x - y) + ay - ax\\
= 3\left( {x - y} \right) - a\left( {x - y} \right)\\
= \left( {x - y} \right)\left( {3 - a} \right)
\end{array}\]

Answer 2

$1, x^{4} + x^{3} - 8 x - 8 = x^{3} . (x + 1) - 8 . (x + 1) = (x + 1) (x^{3} - 8) = (x + 1) (x - 2) (x^{2} + 2 x + 4) 2, x^{2} + x y - x - y = x . (x + y) - (x + y) = (x + y) (x - 1) 3, x y + 1 - x^{2} + y = (x y + y) - (x^{2} - 1) = y . (x + 1) - (x - 1) (x + 1) = (x + 1) (y - x + 1) 4, x y + 2 y - 3 . (x + 2) = y . (x + 2) - 3 (x + 2) = (x + 2) (y - 3) 5, 3 . (x - y) + a y - a x = 3 . (x - y) - a . (x - y) = (x - y) (3 - a)$ .

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Answer 3

$1, x^{4} + x^{3} - 8 x - 8 = x^{3} . (x + 1) - 8 . (x + 1) = (x + 1) (x^{3} - 8) = (x + 1) (x - 2) (x^{2} + 2 x + 4) 2, x^{2} + x y - x - y = x . (x + y) - (x + y) = (x + y) (x - 1) 3, x y + 1 - x^{2} + y = (x y + y) - (x^{2} - 1) = y . (x + 1) - (x - 1) (x + 1) = (x + 1) (y - x + 1) 4, x y + 2 y - 3 . (x + 2) = y . (x + 2) - 3 (x + 2) = (x + 2) (y - 3) 5, 3 . (x - y) + a y - a x = 3 . (x - y) - a . (x - y) = (x - y) (3 - a)$ .

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