Question

Đã trả lời bởi chuyên gia

Answer 1

\[\begin{array}{l}
\left| {x + 1} \right| + \left| y \right| = 2\\
Co:x;y \in Z\\
= > x + 1 \in Z\\
|x + 1| \ge 0\\
|y| \ge 0\\
2 = 0 + 2 = 1 + 1\\
+ )\left\{ \begin{array}{l}
|x + 1| = 0\\
|y| = 2
\end{array} \right.\\
= > \left\{ \begin{array}{l}
x + 1 = 0\\
\left[ \begin{array}{l}
y = 2\\
y = - 2
\end{array} \right.
\end{array} \right.\\
= > \left[ {\begin{array}{*{20}{c}}
{\left\{ \begin{array}{l}
x = - 1\\
y = 2
\end{array} \right.}\\
{\left\{ \begin{array}{l}
x = - 1\\
y = - 2
\end{array} \right.}
\end{array}} \right.\\
+ )\left\{ \begin{array}{l}
|x + 1| = 2\\
|y| = 0
\end{array} \right.\\
= > \left\{ \begin{array}{l}
\left[ \begin{array}{l}
x + 1 = 2\\
x + 1 = - 2
\end{array} \right.\\
y = 0
\end{array} \right.\\
= > \left[ {\begin{array}{*{20}{c}}
{\left\{ \begin{array}{l}
x = 1\\
y = 0
\end{array} \right.}\\
{\left\{ \begin{array}{l}
x = - 3\\
y = 0
\end{array} \right.}
\end{array}} \right.\\
+ )\left\{ \begin{array}{l}
|x + 1| = 1\\
|y| = 1
\end{array} \right.\\
= > \left\{ {\begin{array}{*{20}{c}}
{\left[ \begin{array}{l}
x + 1 = 1\\
x + 1 = - 1
\end{array} \right.}\\
{\left[ \begin{array}{l}
y = 1\\
y = - 1
\end{array} \right.}
\end{array}} \right.\\
= > \left[ {\begin{array}{*{20}{c}}
{\left\{ \begin{array}{l}
x = 0\\
y = 1
\end{array} \right.}\\
{\left\{ \begin{array}{l}
x = 0\\
y = - 1
\end{array} \right.}\\
{\left\{ \begin{array}{l}
x = - 2\\
y = 1
\end{array} \right.}\\
{\left\{ \begin{array}{l}
x = - 2\\
y = - 1
\end{array} \right.}
\end{array}} \right.
\end{array}\]

Vậy nghiệm pt là: (x;y)=(-1;2);(-1;-2);(1;0);(-3;0);(0;1);(0;-1);(-2;1);(-2;-1)

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Answer 2

\[\begin{array}{l}
\left| {x + 1} \right| + \left| y \right| = 2\\
Co:x;y \in Z\\
= > x + 1 \in Z\\
|x + 1| \ge 0\\
|y| \ge 0\\
2 = 0 + 2 = 1 + 1\\
+ )\left\{ \begin{array}{l}
|x + 1| = 0\\
|y| = 2
\end{array} \right.\\
= > \left\{ \begin{array}{l}
x + 1 = 0\\
\left[ \begin{array}{l}
y = 2\\
y = - 2
\end{array} \right.
\end{array} \right.\\
= > \left[ {\begin{array}{*{20}{c}}
{\left\{ \begin{array}{l}
x = - 1\\
y = 2
\end{array} \right.}\\
{\left\{ \begin{array}{l}
x = - 1\\
y = - 2
\end{array} \right.}
\end{array}} \right.\\
+ )\left\{ \begin{array}{l}
|x + 1| = 2\\
|y| = 0
\end{array} \right.\\
= > \left\{ \begin{array}{l}
\left[ \begin{array}{l}
x + 1 = 2\\
x + 1 = - 2
\end{array} \right.\\
y = 0
\end{array} \right.\\
= > \left[ {\begin{array}{*{20}{c}}
{\left\{ \begin{array}{l}
x = 1\\
y = 0
\end{array} \right.}\\
{\left\{ \begin{array}{l}
x = - 3\\
y = 0
\end{array} \right.}
\end{array}} \right.\\
+ )\left\{ \begin{array}{l}
|x + 1| = 1\\
|y| = 1
\end{array} \right.\\
= > \left\{ {\begin{array}{*{20}{c}}
{\left[ \begin{array}{l}
x + 1 = 1\\
x + 1 = - 1
\end{array} \right.}\\
{\left[ \begin{array}{l}
y = 1\\
y = - 1
\end{array} \right.}
\end{array}} \right.\\
= > \left[ {\begin{array}{*{20}{c}}
{\left\{ \begin{array}{l}
x = 0\\
y = 1
\end{array} \right.}\\
{\left\{ \begin{array}{l}
x = 0\\
y = - 1
\end{array} \right.}\\
{\left\{ \begin{array}{l}
x = - 2\\
y = 1
\end{array} \right.}\\
{\left\{ \begin{array}{l}
x = - 2\\
y = - 1
\end{array} \right.}
\end{array}} \right.
\end{array}\]

Vậy nghiệm pt là: (x;y)=(-1;2);(-1;-2);(1;0);(-3;0);(0;1);(0;-1);(-2;1);(-2;-1)

Số thứ tự	Loại hàng	Số lượng (quyển)	Giá đơn vị (đồng)	Tổng số tiền (đồng)
1	Vở loại 1	35	2000	...
2	Vở loại 2	42	1500	...
3	Vở loại 3	38	1200	...
Cộng:				...

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