1) 3 ^ x / 27 = 3
2) x ^ 2002 = x
3) 5 ^ (2x) * .55 ^ x = 625
4) 9 ^ (x - 1) = 9
5) 2 ^ x / (2 ^ 5) = 1 10) 5 ^ (x + 2) = 625
6) (2x + 1) ^ 3 = 125
7) 2014 ^ (2x - 6) = 1
8) 3 ^ x + x ^ 2 = 1
9) (2x - 3) ^ 2 = 81
10) x ^ 199 = x ^ 2
11) (5 ^ (2x) * .5 ^ (x + 1)) / 5 = 125
12) 3 ^ x + 3 ^ (x + 1) + 3 ^ (x + 2) = 243.39
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2 câu trả lời 240
`1 ) 3^x/27 = 3`
`=> 3^x = 3.27`
`=> 3^x = 81`
`=> 3^x = 3^4`
`=>x =4`
Vậy `x = 4`
`2 ) x^2002 = x`
`=> x^2002 - x = 0`
`=> x . (x^2001 -1) =0`
`=> [(x=0) , (x^2001 -1 =0):}`
`=> [(x=0) , (x^2001 = 1):}`
`=> [(x=0) , (x=1):}`
Vậy `x in {0;1}`
`3 ) 5^(2x) .5 . 5^x = 625` ( Đề mình nghĩ )
`=> 5^(2x+1+x) = 5^4`
`=> 2x + 1 + x = 4`
`=> (2+1)x = 4-1`
`=> 3x = 3`
`=> x = 3:3`
`=> x =1`
Vậy `x = 1`
`4 ) 9^(x-1) = 9`
`=> 9^(x-1) =9^1`
`=> x - 1= 1`
`=> x = 1+1`
`=> x =2`
Vậy `x = 2`
`5 ) 2^x/2^5 = 1`
`=> 2^x = 1.2^5`
`=> 2^x = 2^5`
`=> x = 5`
Vậy `x = 5`
`6 ) (2x+1)^3 = 125`
`=> (2x+1)^3 = 5^3`
`=> 2x+1 = 5`
`=> 2x =5-1`
`=> 2x = 4`
`=> x = 4:2`
`=> x = 2`
Vậy `x = 2`
`10 ) 5^(x+2) = 625`
`=> 5^(x+2) = 5^4`
`=> x +2=4`
`=> x = 4-2`
`=> x = 2`
Vậy `x = 2`
`7) 2014 ^ (2x - 6) = 1`
`<=>2x-6=0`
`<=>x=3`
`8) 3 ^ x + x ^ 2 = 1`
`<=> x^2=1-3^x<1`
`x^2<1`
`=>x^2=0`
`=>x=0`
`=>x=1-3^0=1-1=0(tm)``
Vậy` x=0`
`9) (2x - 3) ^ 2 = 81`
`<=> 2x-3=±9`
`=>2x=12;-6`
`=>x=6;-3`
`10) x ^ 199 = x ^ 2`
`x^199=x^2`
`=>x^197=1`
`=>x=1`
`11) (5 ^ (2x) * .5 ^ (x + 1)) / 5 = 125`
`=>5^(2x)*5^(x+1)=5^4`
`=>2x+x+1=4`
`=>3x=3`
`=>x=1`
`12) 3 ^ x + 3 ^ (x + 1) + 3 ^ (x + 2) = 243.39`
`3^x+3^(x+1)+3^(x+2)=3^5*3*13`
`3^x+3^(x+1)+3^(x+2)=3^6*13`
`3^x(1+3+3^2)=3^6*13`
`=>3^x*13=3^6*13`
`=>x=6`
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