Question

Đã trả lời bởi chuyên gia

Answer 1

TA có:

$A = \frac{1}{3} + \frac{1}{6} + \frac{1}{12} + \frac{1}{24} + \frac{1}{48} + \frac{1}{96} + \frac{1}{192} + \frac{1}{384} \Rightarrow 2 A = \frac{2}{3} + \frac{1}{3} + \frac{1}{6} + \frac{1}{12} + \frac{1}{24} + \frac{1}{48} + \frac{1}{96} + \frac{1}{192} = \frac{2}{3} + (\frac{1}{3} + \frac{1}{6} + \frac{1}{12} + \frac{1}{24} + \frac{1}{48} + \frac{1}{96} + \frac{1}{192} + \frac{1}{384}) - \frac{1}{384} = \frac{2}{3} + A - \frac{1}{384} \Rightarrow A = \frac{2}{3} - \frac{1}{384} = \frac{85}{128}$

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Answer 2

TA có:

$A = \frac{1}{3} + \frac{1}{6} + \frac{1}{12} + \frac{1}{24} + \frac{1}{48} + \frac{1}{96} + \frac{1}{192} + \frac{1}{384} \Rightarrow 2 A = \frac{2}{3} + \frac{1}{3} + \frac{1}{6} + \frac{1}{12} + \frac{1}{24} + \frac{1}{48} + \frac{1}{96} + \frac{1}{192} = \frac{2}{3} + (\frac{1}{3} + \frac{1}{6} + \frac{1}{12} + \frac{1}{24} + \frac{1}{48} + \frac{1}{96} + \frac{1}{192} + \frac{1}{384}) - \frac{1}{384} = \frac{2}{3} + A - \frac{1}{384} \Rightarrow A = \frac{2}{3} - \frac{1}{384} = \frac{85}{128}$

Answer 3

$A = \frac{1}{3} + \frac{1}{6} + \frac{1}{12} + \frac{1}{24} + \frac{1}{48} + \frac{1}{96} + \frac{1}{192} + \frac{1}{384} 2 A = \frac{2}{3} + \frac{1}{3} + \frac{1}{6} + \frac{1}{12} + \frac{1}{24} + \frac{1}{48} + \frac{1}{96} + \frac{1}{192} \Rightarrow A = 2 A - A = \frac{2}{3} - \frac{1}{384} = \frac{85}{128} V ậ y A = \frac{85}{128}$ ..

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Answer 4

$A = \frac{1}{3} + \frac{1}{6} + \frac{1}{12} + \frac{1}{24} + \frac{1}{48} + \frac{1}{96} + \frac{1}{192} + \frac{1}{384} 2 A = \frac{2}{3} + \frac{1}{3} + \frac{1}{6} + \frac{1}{12} + \frac{1}{24} + \frac{1}{48} + \frac{1}{96} + \frac{1}{192} \Rightarrow A = 2 A - A = \frac{2}{3} - \frac{1}{384} = \frac{85}{128} V ậ y A = \frac{85}{128}$ ..

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