Question

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Answer 1

$\frac{1}{2} + \frac{1}{6} + \frac{1}{12} + \frac{1}{20} + \frac{1}{30} + \frac{1}{42} + \frac{1}{56} + \frac{1}{72} + \frac{1}{90} + \frac{1}{100} = \frac{1}{1 \times 2} + \frac{1}{2 \times 3} + \frac{1}{3 \times 4} + \frac{1}{4 \times 5} + . . . + \frac{1}{9 \times 10} + \frac{1}{100} = 1 - \frac{1}{2} + \frac{1}{2} - \frac{1}{3} + \frac{1}{3} - \frac{1}{4} + \frac{1}{4} - \frac{1}{5} + . . . + \frac{1}{9} - \frac{1}{10} + \frac{1}{100} = 1 - \frac{1}{10} + \frac{1}{100} = \frac{100}{100} - \frac{10}{100} + \frac{1}{100} = \frac{91}{100}$ .

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Answer 2

$\frac{1}{2} + \frac{1}{6} + \frac{1}{12} + \frac{1}{20} + \frac{1}{30} + \frac{1}{42} + \frac{1}{56} + \frac{1}{72} + \frac{1}{90} + \frac{1}{100} = \frac{1}{1 \times 2} + \frac{1}{2 \times 3} + \frac{1}{3 \times 4} + \frac{1}{4 \times 5} + . . . + \frac{1}{9 \times 10} + \frac{1}{100} = 1 - \frac{1}{2} + \frac{1}{2} - \frac{1}{3} + \frac{1}{3} - \frac{1}{4} + \frac{1}{4} - \frac{1}{5} + . . . + \frac{1}{9} - \frac{1}{10} + \frac{1}{100} = 1 - \frac{1}{10} + \frac{1}{100} = \frac{100}{100} - \frac{10}{100} + \frac{1}{100} = \frac{91}{100}$ .

Answer 3

$\frac{1}{2} + \frac{1}{6} + \frac{1}{12} + \frac{1}{20} + \frac{1}{30} + \frac{1}{42} + \frac{1}{56} + \frac{1}{72} + \frac{1}{90} + \frac{1}{100} = \frac{1}{2} + \frac{1}{2.3} + \frac{1}{3.4} + \frac{1}{4.5} + \frac{1}{5.6} + \frac{1}{6.7} + \frac{1}{7.8} + \frac{1}{8.9} + \frac{1}{9.10} + \frac{1}{10.10} = \frac{1}{2} + \frac{1}{2} - \frac{1}{3} + \frac{1}{3} - \frac{1}{4} + \frac{1}{4} - \frac{1}{5} + \frac{1}{5} - \frac{1}{6} + \frac{1}{6} - \frac{1}{7} + \frac{1}{7} - \frac{1}{8} + \frac{1}{8} - \frac{1}{9} + \frac{1}{9} - \frac{1}{10} + \frac{1}{100} = \frac{1}{2} + \frac{1}{2} - \frac{1}{10} + \frac{1}{100} = 1 - \frac{1}{10} + \frac{1}{100} = \frac{100}{100} - \frac{10}{100} + \frac{1}{100} = \frac{91}{10}$ .

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Answer 4

$\frac{1}{2} + \frac{1}{6} + \frac{1}{12} + \frac{1}{20} + \frac{1}{30} + \frac{1}{42} + \frac{1}{56} + \frac{1}{72} + \frac{1}{90} + \frac{1}{100} = \frac{1}{2} + \frac{1}{2.3} + \frac{1}{3.4} + \frac{1}{4.5} + \frac{1}{5.6} + \frac{1}{6.7} + \frac{1}{7.8} + \frac{1}{8.9} + \frac{1}{9.10} + \frac{1}{10.10} = \frac{1}{2} + \frac{1}{2} - \frac{1}{3} + \frac{1}{3} - \frac{1}{4} + \frac{1}{4} - \frac{1}{5} + \frac{1}{5} - \frac{1}{6} + \frac{1}{6} - \frac{1}{7} + \frac{1}{7} - \frac{1}{8} + \frac{1}{8} - \frac{1}{9} + \frac{1}{9} - \frac{1}{10} + \frac{1}{100} = \frac{1}{2} + \frac{1}{2} - \frac{1}{10} + \frac{1}{100} = 1 - \frac{1}{10} + \frac{1}{100} = \frac{100}{100} - \frac{10}{100} + \frac{1}{100} = \frac{91}{10}$ .

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