Question

Đã trả lời bởi chuyên gia

Answer 1

$a, 2 x . {(x + 1)}^{2} - {(x - 1)}^{3} - (x - 2) (x^{2} + 2 x + 4) = 2 x . (x^{2} + 2 x + 1) - (x^{3} - 3 x^{2} + 3 x - 1) - (x^{3} - 8) = 2 x^{3} + 4 x^{2} + 2 x - x^{3} + 3 x^{2} - 3 x + 1 - x^{3} + 8 = 7 x^{2} - x + 9 b, (x + 5) (x - 5) (x + 2) - {(x + 2)}^{2} = (x^{2} - 25) (x + 2) - (x^{2} + 4 x + 4) = x^{3} + 2 x^{2} - 25 x - 50 - x^{2} - 4 x - 4 = x^{3} + x^{2} - 29 x - 54 c, {(x + 3)}^{3} + (x - 5) (x^{2} + 5 x + 25) - (x - 1) (x^{2} + x + 1) = x^{3} + 9 x^{2} + 27 x + 27 + x^{3} - 125 - x^{3} + 1 = x^{3} + 9 x^{2} + 27 x - 99$

$d, (2 x + 3) (4 x^{2} - 6 x + 9) - 2 . (4 x^{3} - 1) = 8 x^{3} + 27 - 8 x^{3} + 2 = 29 e, {(x - 1)}^{3} - (x + 2) (x^{2} - 2 x + 4) + 3 x^{2} + 2 x = x^{3} - 3 x^{2} + 3 x - 1 - x^{3} - 8 + 3 x^{2} + 2 x = 5 x - 9 f, {(x - 1)}^{3} + (2 - x) (4 + 2 x + x^{2}) = x^{3} - 3 x^{2} + 3 x - 1 + 8 - x^{3} = - 3 x^{2} + 3 x + 7$

$g, {(x - 2)}^{3} + (x - 3) (x^{2} + 3 x + 9) + {(x + 1)}^{3} = x^{3} - 6 x^{2} + 12 x - 8 + x^{3} - 27 + x^{3} + 3 x^{2} + 3 x + 1 = 3 x^{3} - 3 x^{2} + 15 x - 34 h, x (x + 5) (x - 5) - (x + 2) (x^{2} - 2 x + 4) = x . (x^{2} - 25) - (x^{3} + 8) = x^{3} - 25 x - x^{3} - 8 = - 25 x - 8$ .

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Answer 2

$a, 2 x . {(x + 1)}^{2} - {(x - 1)}^{3} - (x - 2) (x^{2} + 2 x + 4) = 2 x . (x^{2} + 2 x + 1) - (x^{3} - 3 x^{2} + 3 x - 1) - (x^{3} - 8) = 2 x^{3} + 4 x^{2} + 2 x - x^{3} + 3 x^{2} - 3 x + 1 - x^{3} + 8 = 7 x^{2} - x + 9 b, (x + 5) (x - 5) (x + 2) - {(x + 2)}^{2} = (x^{2} - 25) (x + 2) - (x^{2} + 4 x + 4) = x^{3} + 2 x^{2} - 25 x - 50 - x^{2} - 4 x - 4 = x^{3} + x^{2} - 29 x - 54 c, {(x + 3)}^{3} + (x - 5) (x^{2} + 5 x + 25) - (x - 1) (x^{2} + x + 1) = x^{3} + 9 x^{2} + 27 x + 27 + x^{3} - 125 - x^{3} + 1 = x^{3} + 9 x^{2} + 27 x - 99$

$d, (2 x + 3) (4 x^{2} - 6 x + 9) - 2 . (4 x^{3} - 1) = 8 x^{3} + 27 - 8 x^{3} + 2 = 29 e, {(x - 1)}^{3} - (x + 2) (x^{2} - 2 x + 4) + 3 x^{2} + 2 x = x^{3} - 3 x^{2} + 3 x - 1 - x^{3} - 8 + 3 x^{2} + 2 x = 5 x - 9 f, {(x - 1)}^{3} + (2 - x) (4 + 2 x + x^{2}) = x^{3} - 3 x^{2} + 3 x - 1 + 8 - x^{3} = - 3 x^{2} + 3 x + 7$

$g, {(x - 2)}^{3} + (x - 3) (x^{2} + 3 x + 9) + {(x + 1)}^{3} = x^{3} - 6 x^{2} + 12 x - 8 + x^{3} - 27 + x^{3} + 3 x^{2} + 3 x + 1 = 3 x^{3} - 3 x^{2} + 15 x - 34 h, x (x + 5) (x - 5) - (x + 2) (x^{2} - 2 x + 4) = x . (x^{2} - 25) - (x^{3} + 8) = x^{3} - 25 x - x^{3} - 8 = - 25 x - 8$ .

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