Question

Đã trả lời bởi chuyên gia

Answer 1

ta có:

$D . \frac{5}{6} + \frac{2}{3} = \frac{5}{6} + \frac{4}{6} = \frac{9}{6} = \frac{3}{2} \frac{3}{4} : 2 = \frac{3}{4} \times \frac{1}{2} = \frac{3}{8} \frac{5}{6} - \frac{3}{8} = \frac{40}{48} - \frac{18}{48} = \frac{22}{48} = \frac{11}{24} \frac{5}{6} \times \frac{3}{8} = \frac{5 \times 3}{6 \times 8} = \frac{5 \times 1}{2 \times 8} = \frac{5}{16} 5 \times \frac{2}{3} + \frac{1}{6} = \frac{10}{3} + \frac{1}{6} = \frac{20}{6} + \frac{1}{6} = \frac{21}{6} E . 3 + \frac{2}{3} = \frac{9}{3} + \frac{2}{3} = \frac{11}{3} 3 - \frac{5}{6} = \frac{18}{6} - \frac{5}{6} = \frac{13}{6} 3 : \frac{3}{8} = 3 \times \frac{8}{3} = 8 \frac{1}{2} \times 14 = \frac{14}{2} = 7 \frac{1}{2} + \frac{2}{3} \times \frac{3}{4} + \frac{4}{5} - 1 = \frac{1}{2} + \frac{2}{4} + \frac{4}{5} - 1 = \frac{4}{5}$

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Answer 2

ta có:

$D . \frac{5}{6} + \frac{2}{3} = \frac{5}{6} + \frac{4}{6} = \frac{9}{6} = \frac{3}{2} \frac{3}{4} : 2 = \frac{3}{4} \times \frac{1}{2} = \frac{3}{8} \frac{5}{6} - \frac{3}{8} = \frac{40}{48} - \frac{18}{48} = \frac{22}{48} = \frac{11}{24} \frac{5}{6} \times \frac{3}{8} = \frac{5 \times 3}{6 \times 8} = \frac{5 \times 1}{2 \times 8} = \frac{5}{16} 5 \times \frac{2}{3} + \frac{1}{6} = \frac{10}{3} + \frac{1}{6} = \frac{20}{6} + \frac{1}{6} = \frac{21}{6} E . 3 + \frac{2}{3} = \frac{9}{3} + \frac{2}{3} = \frac{11}{3} 3 - \frac{5}{6} = \frac{18}{6} - \frac{5}{6} = \frac{13}{6} 3 : \frac{3}{8} = 3 \times \frac{8}{3} = 8 \frac{1}{2} \times 14 = \frac{14}{2} = 7 \frac{1}{2} + \frac{2}{3} \times \frac{3}{4} + \frac{4}{5} - 1 = \frac{1}{2} + \frac{2}{4} + \frac{4}{5} - 1 = \frac{4}{5}$

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