Question

Đã trả lời bởi chuyên gia

Answer 1

Ta có:

$\frac{1}{3} + \frac{2}{4} \times \frac{1}{2} = \frac{1}{3} + \frac{1}{4} = \frac{4}{12} + \frac{3}{12} = \frac{7}{12} \frac{6}{7} : \frac{1}{7} + \frac{2}{5} = \frac{6}{7} \times 7 + \frac{2}{5} = 6 + \frac{2}{5} = \frac{30}{5} + \frac{2}{5} = \frac{32}{5} \frac{3}{2} - \frac{1}{2} : \frac{1}{3} = \frac{3}{2} - \frac{1}{2} \times 3 = \frac{3}{2} - \frac{3}{2} = 0$

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Answer 2

Ta có:

$\frac{1}{3} + \frac{2}{4} \times \frac{1}{2} = \frac{1}{3} + \frac{1}{4} = \frac{4}{12} + \frac{3}{12} = \frac{7}{12} \frac{6}{7} : \frac{1}{7} + \frac{2}{5} = \frac{6}{7} \times 7 + \frac{2}{5} = 6 + \frac{2}{5} = \frac{30}{5} + \frac{2}{5} = \frac{32}{5} \frac{3}{2} - \frac{1}{2} : \frac{1}{3} = \frac{3}{2} - \frac{1}{2} \times 3 = \frac{3}{2} - \frac{3}{2} = 0$

Answer 3

$\frac{1}{3} + \frac{2}{4} \times \frac{1}{2} = \frac{1}{3} + \frac{1}{4} = \frac{4 + 3}{12} = \frac{7}{12}$

$\frac{6}{7} : \frac{1}{7} + \frac{2}{5} = \frac{2}{5} + \frac{6}{7} \times 7 = \frac{2}{5} + 6 = \frac{2 + 30}{5} = \frac{32}{5}$

$\frac{3}{2} - \frac{1}{2} : \frac{1}{3} = \frac{3}{2} - \frac{1}{2} \times 3 = \frac{3}{2} - \frac{3}{2} = 0$

..

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Answer 4

$\frac{1}{3} + \frac{2}{4} \times \frac{1}{2} = \frac{1}{3} + \frac{1}{4} = \frac{4 + 3}{12} = \frac{7}{12}$

$\frac{6}{7} : \frac{1}{7} + \frac{2}{5} = \frac{2}{5} + \frac{6}{7} \times 7 = \frac{2}{5} + 6 = \frac{2 + 30}{5} = \frac{32}{5}$

$\frac{3}{2} - \frac{1}{2} : \frac{1}{3} = \frac{3}{2} - \frac{1}{2} \times 3 = \frac{3}{2} - \frac{3}{2} = 0$

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Answer 5

a, $\frac{1}{3} + \frac{2}{4} \times \frac{1}{2} = \frac{1}{3} + \frac{1}{4} = \frac{7}{12}$

b, $\frac{6}{7} \div \frac{1}{7} + \frac{2}{5} = 6 + \frac{2}{5} = \frac{32}{5}$

c, $\frac{3}{2} - \frac{1}{2} \div \frac{1}{3} = \frac{3}{2} - \frac{3}{2} = 0$

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