a) The balanced chemical equation for the neutralization reaction between hydrochloric acid (HCl) and potassium hydroxide (KOH) is:

HCl+KOH→KCl+H2OHCl+KOH→KCl+H2​O
b) To find the volume of KOH used, we start with the concept of moles. The amount of HCl in the 200 ml solution at 2M is:

nHCl=C×V=2 mol/L×0.2 L=0.4 molnHCl​=C×V=2mol/L×0.2L=0.4mol
Since the reaction ratio is 1:1, the moles of KOH needed is also 0.4 mol. The concentration of KOH is 1M, thus the volume needed is:

VKOH=nKOHCKOH=0.4 mol1 mol/L=0.4 L=400 mlVKOH​=CKOH​nKOH​​=1mol/L0.4mol​=0.4L=400ml
c) The mass of the salt (KCl) produced can be calculated using the moles calculated earlier (0.4 mol). The molar mass of KCl is approximately 74.55 g/mol. Thus, the mass of KCl is:

mKCl=nKCl×MKCl=0.4 mol×74.55 g/mol=29.82 gmKCl​=nKCl​×MKCl​=0.4mol×74.55g/mol