Question

Đã trả lời bởi chuyên gia

Answer 1

a)(571+129)+(216+124)

=700+340

=1040

Answer 2

571+216=787571+216=787
787+129=916787+129=916
916+124=1040916+124=1040
**Result:** 1040 ### Part b: **Calculate 27.74 + 26.27 - 355** 27.74+26.27=54.0127.74+26.27=54.01
54.01−355=−300.9954.01−355=−300.99
**Result:** -300.99 ### Part c: **Calculate 100 : (250 : (450 - (4.53 \times 4.53 - 22.25 \times 22.25)))** 1. Calculate4.53×4.534.53×4.53: 4.53×4.53=20.52094.53×4.53=20.5209
2. Calculate22.25×22.2522.25×22.25: 22.25×22.25=495.062522.25×22.25=495.0625
3. Subtract20.520920.5209 from495.0625495.0625: 450−(20.5209−495.0625)=450−(−474.5416)=450+474.5416=924.5416450−(20.5209−495.0625)=450−(−474.5416)=450+474.5416=924.5416
4. Calculate250:924.5416250:924.5416: 250:924.5416≈0.270250:924.5416≈0.270
5. Finally calculate100:0.270100:0.270: 100:0.270≈370.37100:0.270≈370.37
### Solving for x: **1. Findx� in the equation5.4x+42+x=3665.4�+42+�=366** 5.4x+x+42=3665.4�+�+42=366
6.4x+42=3666.4�+42=366
6.4x=366−426.4�=366−42
6.4x=3246.4�=324
x=3246.4≈50.625�=3246.4≈50.625
**2. Findx� such thatx� is a multiple of 11 and 10, andx<40�<40** - The least common multiple of 10 and 11 is110110. The only multiples of 10 less than 40 are10,20,3010,20,30. - The multiples of 11 less than 40 are11,22,3311,22,33. - There are no common multiples of both that are less than 40. Therefore, you can state: There is **no value ofx�** that satisfiesx<40�<40 that is a multiple of both 10 and 11.

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Answer 3

571+216=787571+216=787
787+129=916787+129=916
916+124=1040916+124=1040
**Result:** 1040 ### Part b: **Calculate 27.74 + 26.27 - 355** 27.74+26.27=54.0127.74+26.27=54.01
54.01−355=−300.9954.01−355=−300.99
**Result:** -300.99 ### Part c: **Calculate 100 : (250 : (450 - (4.53 \times 4.53 - 22.25 \times 22.25)))** 1. Calculate4.53×4.534.53×4.53: 4.53×4.53=20.52094.53×4.53=20.5209
2. Calculate22.25×22.2522.25×22.25: 22.25×22.25=495.062522.25×22.25=495.0625
3. Subtract20.520920.5209 from495.0625495.0625: 450−(20.5209−495.0625)=450−(−474.5416)=450+474.5416=924.5416450−(20.5209−495.0625)=450−(−474.5416)=450+474.5416=924.5416
4. Calculate250:924.5416250:924.5416: 250:924.5416≈0.270250:924.5416≈0.270
5. Finally calculate100:0.270100:0.270: 100:0.270≈370.37100:0.270≈370.37
### Solving for x: **1. Findx� in the equation5.4x+42+x=3665.4�+42+�=366** 5.4x+x+42=3665.4�+�+42=366
6.4x+42=3666.4�+42=366
6.4x=366−426.4�=366−42
6.4x=3246.4�=324
x=3246.4≈50.625�=3246.4≈50.625
**2. Findx� such thatx� is a multiple of 11 and 10, andx<40�<40** - The least common multiple of 10 and 11 is110110. The only multiples of 10 less than 40 are10,20,3010,20,30. - The multiples of 11 less than 40 are11,22,3311,22,33. - There are no common multiples of both that are less than 40. Therefore, you can state: There is **no value ofx�** that satisfiesx<40�<40 that is a multiple of both 10 and 11.

Answer 4

a) (571+129)+(216+124)

= 700+340=1040

b) 27.(74+26)-355=27.100-355=2700-355=?

còn lại tự làm ik

Answer 5

a) 571 + 216 + 129 + 124

= (571 + 129) + (216 + 124)

= 700 + 340

= 1040

b) 27 . 74 + 26 . 27 - 355

= 27 . (74 + 26) - 355

= 27 . 100 - 355

= 2700 - 355

= 2345

c) 100 : {250 : [450 - (4 . 5³ - 2² . 25)]} + 2024⁰

= 100 : {250 : [450 - (4 . 125 - 4 . 25)]} + 1

= 100 : {250 : [450 - 4 . (125 - 25)]} + 1

= 100 : {250 : [450 - 4 . 100]} + 1

= 100 : {250 : [450 - 400]} + 1

= 100 : {250 : 50} + 1

= 100 : 5 + 1

= 20 + 1

= 21

-----------------------------

5 . 4x + 42 + x = 366

20x + 42 + x = 366

(20x + x) + 42 = 366

21x + 42 = 366

21x = 366 - 42

21x = 324

x = $\frac{108}{7}$

Vậy x = $\frac{108}{7}$
PHẦN CUỐI BẠN XEM LẠI ĐỀ BÀI ĐÃ ĐÚNG CHƯA Ạ!

Số thứ tự	Loại hàng	Số lượng (quyển)	Giá đơn vị (đồng)	Tổng số tiền (đồng)
1	Vở loại 1	35	2000	...
2	Vở loại 2	42	1500	...
3	Vở loại 3	38	1200	...
Cộng:				...

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