Question

Đã trả lời bởi chuyên gia

Answer 1

ta có:

$a . \frac{4}{5} + \frac{1}{4} : x = 2 = > \frac{1}{4} : x = 2 - \frac{4}{5} = > \frac{1}{4} : x = \frac{10 - 4}{5} = > \frac{1}{4} : x = \frac{6}{5} = > x = \frac{1}{4} : \frac{6}{5} = > x = \frac{1}{4} \times \frac{5}{6} = > x = \frac{5}{24} b . X + X : 3 \times 4 + X : 3 \times 7 + X : 6 \times 26 = 117 = > X + X \times \frac{4}{3} + X \times \frac{7}{3} + X \times \frac{26}{6} = 117 = > X \times (1 + \frac{4}{3} + \frac{7}{3} + \frac{26}{6}) = 117 = > X \times (\frac{6 + 8 + 14 + 26}{6}) = 117 = > X \times \frac{54}{6} = 117 = > X \times 9 = 117 = > X = 13 c . X - 0, 1 + X : 0, 125 + X : 0, 25 + X : 0, 5 = 120 = > X + X : 0, 125 + X : 0, 25 + X : 0, 5 = 120 + 0, 1 = > X \times (1 + \frac{1}{0, 125} + \frac{1}{0, 25} + \frac{1}{0, 5}) = 120, 1 = > X \times (1 + 8 + 4 + 2) = 120, 1 = > X \times 15 = 120, 1 = > X = 120, 1 : 15 = > X = \frac{1201}{150}$

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Answer 2

ta có:

$a . \frac{4}{5} + \frac{1}{4} : x = 2 = > \frac{1}{4} : x = 2 - \frac{4}{5} = > \frac{1}{4} : x = \frac{10 - 4}{5} = > \frac{1}{4} : x = \frac{6}{5} = > x = \frac{1}{4} : \frac{6}{5} = > x = \frac{1}{4} \times \frac{5}{6} = > x = \frac{5}{24} b . X + X : 3 \times 4 + X : 3 \times 7 + X : 6 \times 26 = 117 = > X + X \times \frac{4}{3} + X \times \frac{7}{3} + X \times \frac{26}{6} = 117 = > X \times (1 + \frac{4}{3} + \frac{7}{3} + \frac{26}{6}) = 117 = > X \times (\frac{6 + 8 + 14 + 26}{6}) = 117 = > X \times \frac{54}{6} = 117 = > X \times 9 = 117 = > X = 13 c . X - 0, 1 + X : 0, 125 + X : 0, 25 + X : 0, 5 = 120 = > X + X : 0, 125 + X : 0, 25 + X : 0, 5 = 120 + 0, 1 = > X \times (1 + \frac{1}{0, 125} + \frac{1}{0, 25} + \frac{1}{0, 5}) = 120, 1 = > X \times (1 + 8 + 4 + 2) = 120, 1 = > X \times 15 = 120, 1 = > X = 120, 1 : 15 = > X = \frac{1201}{150}$

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