Question

Đã trả lời bởi chuyên gia

Answer 1

$g ọ i s ố m o l c ủ a N a C l, N a B r, N a I l à a m o l (v ì s ô m o l b ằ n g n h a u) \Rightarrow m_{X} = 58, 5 a + 103 a + 150 a = 3, 115 \Rightarrow a = 0, 01 m o l * G ọ i s ố m o l N a B r p / ư l à x m o l C l_{2} + 2 N a B r - > 2 N a C l + B r_{2} (1) x / 2 . . . . x . . . . . . . . . . . . . . . . x C l_{2} + 2 N a I - > 2 N a C l + I_{2} (2) 0, 01 / 2 . . . . 0, 01 . . . . . . . . . . . . . 0, 01 * d d Y : N a C l, N a B r d ư n N a C l = n_{N a C l b a n đ ầ u} + n_{N a C l s p} = 0, 01 + x + 0, 0, 1 = 0, 02 + x (m o l) n_{N a B r} = 0, 01 - x (m o l) * N a C l + A g N O_{3} \to A g C l + N a N O_{3} 0, 02 + x . . . . . . . . . . . . . . . . 0, 02 + x N a B r_{d ư} + A g N O_{3} \to A g B r + N a N O_{3} 0, 01 - x . . . . . . . . . . . . . . . . 0, 01 - x n_{k ế t t ủ a A g C l} = 0, 02 + x + 0, 01 - x = 0, 03 m o l m_{k ế t t ủ a} = (o, o 2 + x) . 143, 5 + (0, 01 - x) . 188 = 4, 5275 \Rightarrow x = 0, 005 m o l * n_{C l_{2}} = x / 2 + 0, 01 / 2 = 0, 005 / 2 + 0, 01 / 2 = 0, 0075 m o l V_{C l_{2}} = n . 22, 4 = 0, 0075.22, 4 = 0, 168 l í t$

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Answer 2

$g ọ i s ố m o l c ủ a N a C l, N a B r, N a I l à a m o l (v ì s ô m o l b ằ n g n h a u) \Rightarrow m_{X} = 58, 5 a + 103 a + 150 a = 3, 115 \Rightarrow a = 0, 01 m o l * G ọ i s ố m o l N a B r p / ư l à x m o l C l_{2} + 2 N a B r - > 2 N a C l + B r_{2} (1) x / 2 . . . . x . . . . . . . . . . . . . . . . x C l_{2} + 2 N a I - > 2 N a C l + I_{2} (2) 0, 01 / 2 . . . . 0, 01 . . . . . . . . . . . . . 0, 01 * d d Y : N a C l, N a B r d ư n N a C l = n_{N a C l b a n đ ầ u} + n_{N a C l s p} = 0, 01 + x + 0, 0, 1 = 0, 02 + x (m o l) n_{N a B r} = 0, 01 - x (m o l) * N a C l + A g N O_{3} \to A g C l + N a N O_{3} 0, 02 + x . . . . . . . . . . . . . . . . 0, 02 + x N a B r_{d ư} + A g N O_{3} \to A g B r + N a N O_{3} 0, 01 - x . . . . . . . . . . . . . . . . 0, 01 - x n_{k ế t t ủ a A g C l} = 0, 02 + x + 0, 01 - x = 0, 03 m o l m_{k ế t t ủ a} = (o, o 2 + x) . 143, 5 + (0, 01 - x) . 188 = 4, 5275 \Rightarrow x = 0, 005 m o l * n_{C l_{2}} = x / 2 + 0, 01 / 2 = 0, 005 / 2 + 0, 01 / 2 = 0, 0075 m o l V_{C l_{2}} = n . 22, 4 = 0, 0075.22, 4 = 0, 168 l í t$

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