Bài 8: Tinh khối lượng của các chất sau đây:

a, 0,5 mol HCl

$\Rightarrow {\mathrm{m}}_{\mathrm{HCl}}=0,5.36,5=18,25 \left(\mathrm{g}\right)$

$$\begin{gathered} \mathrm{b}, 0,75 \mathrm{mol} {\mathrm{Al}}_2{\left({\mathrm{SO}}_4\right)}_3 \Rightarrow {\mathrm{m}}_{{\mathrm{Al}}_2{\left({\mathrm{SO}}_4\right)}_3 }=0,75. 342=256,5 \left(\mathrm{g}\right) \\ \mathrm{c}. 3,36 \mathrm{lít} \mathrm{khí} {\mathrm{CH}}_4 \left(\mathrm{đktc}\right) \\ \Rightarrow {\mathrm{n}}_{{\mathrm{CH}}_4}=\frac{3,36}{22,4}=0,15 \left(\mathrm{mol}\right) \\ \Rightarrow {\mathrm{m}}_{{\mathrm{CH}}_4}=0,15.16=2,4 \left(\mathrm{g}\right) \\ \mathrm{d}, 6,72 \mathrm{lít} \mathrm{khi} {\mathrm{NH}}_3 \left(\mathrm{đktc}\right) \\ \Rightarrow {\mathrm{n}}_{{\mathrm{NH}}_3}=\frac{6,72}{22,4}=0,3 \left(\mathrm{mol}\right) \\ \Rightarrow {\mathrm{m}}_{{\mathrm{NH}}_3}=0,3.17=5,1 \left(\mathrm{g}\right) \end{gathered}$$

Bài 9: Tinh thể tích (đktc) của các chất sau đây:

$$\begin{gathered} \mathrm{a}, 0,25 \mathrm{mol} \mathrm{khí} {\mathrm{NH}}_3 \\ \Rightarrow {\mathrm{V}}_{{\mathrm{NH}}_3}=0,25.22,4=5,6 \left(\mathrm{l}\right) \\ \mathrm{b}, 0,7 \mathrm{mol} \mathrm{khi} {\mathrm{N}}_2 \\ \Rightarrow {\mathrm{V}}_{{\mathrm{N}}_2}=0,7.22,4=15,68 \left(\mathrm{l}\right) \\ \mathrm{c}, 3,2 \mathrm{gam} {\mathrm{SO}}_2 \\ \Rightarrow {\mathrm{V}}_{{\mathrm{SO}}_2}=0,25.22,4=5,6 \left(\mathrm{l}\right) \\ \mathrm{d}, 6,4 \mathrm{gam} \mathrm{khí} {\mathrm{O}}_2 \\ \Rightarrow {\mathrm{n}}_{{\mathrm{O}}_2}=\frac{6,4}{32}=0,2 \left(\mathrm{mol}\right) \\ \Rightarrow {\mathrm{V}}_{{\mathrm{O}}_2}=0,2.22,4 =4,48 \left(\mathrm{l}\right) \\ \mathrm{e}, 0,25 \mathrm{mol} \mathrm{NaOH} \\ \Rightarrow {\mathrm{V}}_{\mathrm{NaOH}}=0,25.22,4=5,6 \left(\mathrm{l}\right) \\ \mathrm{f}, 0,4\mathrm{mol} \mathrm{Fe}{\left({\mathrm{NO}}_3\right)}_2 \\ \Rightarrow {\mathrm{V}}_{\mathrm{Fe}{\left({\mathrm{NO}}_3\right)}_2 }=0,4.22,4=8,96 \left(\mathrm{l}\right) \\ \mathrm{g}, 3,36 \mathrm{lít} \mathrm{khi} {\mathrm{H}}_2\mathrm{S} \left(\mathrm{đktc}\right) \\ \mathrm{h}, 8,96 \mathrm{lít} \mathrm{khí} {\mathrm{CH}}_4 \left(\mathrm{đktc}\right) \\ \mathrm{i}, 0,2 \mathrm{mol} \mathrm{khí} {\mathrm{CO}}_2 \\ \Rightarrow {\mathrm{V}}_{{\mathrm{CO}}_2}=0,2.22,4=4,48 \left(\mathrm{l}\right) \\ \mathrm{k}, 0.8 \mathrm{mol} \mathrm{khí} {\mathrm{H}}_2 \\ \Rightarrow {\mathrm{V}}_{{\mathrm{H}}_2}=0,8.22,4=17,92 \left(\mathrm{l}\right) \\ \mathrm{l}, 3,4 \mathrm{gam} \mathrm{khi} {\mathrm{NH}}_3 \\ \Rightarrow {\mathrm{n}}_{{\mathrm{NH}}_3}=\frac{3,4}{17}=0,2 \left(\mathrm{mol}\right) \\ \Rightarrow {\mathrm{V}}_{{\mathrm{NH}}_3}=0,2.22,4 =4,48 \left(\mathrm{l}\right) \\ \mathrm{m}, 3,4 \mathrm{gam} \mathrm{khi} {\mathrm{H}}_2\mathrm{S} \\ \Rightarrow {\mathrm{n}}_{{\mathrm{H}}_2\mathrm{S}}=\frac{3,4}{34}=0,1 \left(\mathrm{mol}\right) \\ \Rightarrow {\mathrm{V}}_{{\mathrm{H}}_2\mathrm{S}}=0,1.22,4 =2,24 \left(\mathrm{l}\right) \end{gathered}$$