Question

Đã trả lời bởi chuyên gia

Answer 1

$\frac{\sqrt[3]{2 \sqrt{8}}}{\sqrt[3]{\sqrt[3]{4}}} = \frac{\sqrt[3]{2 . \sqrt{2^{3}}}}{\sqrt[3]{\sqrt[3]{2^{2}}}} = \frac{\sqrt[3]{2 . 2^{\frac{3}{2}}}}{\sqrt[3]{2^{\frac{2}{3}}}} = \sqrt[3]{\frac{2 . 2^{\frac{3}{2}}}{2^{\frac{2}{3}}}} = \sqrt[3]{\frac{2^{\frac{5}{2}}}{2^{\frac{2}{3}}}} = \sqrt[3]{2^{\frac{11}{6}}} = 2^{\frac{11}{6} : 3} = 2^{\frac{11}{18}}$ ..

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Answer 2

$\frac{\sqrt[3]{2 \sqrt{8}}}{\sqrt[3]{\sqrt[3]{4}}} = \frac{\sqrt[3]{2 . \sqrt{2^{3}}}}{\sqrt[3]{\sqrt[3]{2^{2}}}} = \frac{\sqrt[3]{2 . 2^{\frac{3}{2}}}}{\sqrt[3]{2^{\frac{2}{3}}}} = \sqrt[3]{\frac{2 . 2^{\frac{3}{2}}}{2^{\frac{2}{3}}}} = \sqrt[3]{\frac{2^{\frac{5}{2}}}{2^{\frac{2}{3}}}} = \sqrt[3]{2^{\frac{11}{6}}} = 2^{\frac{11}{6} : 3} = 2^{\frac{11}{18}}$ ..

Answer 3

$\frac{\sqrt[3]{2 \sqrt{8}}}{\sqrt[3]{\sqrt[3]{4}}} = \sqrt[3]{\frac{2 \sqrt{8}}{\sqrt[3]{4}}} - X é t \frac{2 \sqrt{2^{3}}}{\sqrt[3]{2^{2}}} = \frac{2 x 2^{\frac{3}{2}}}{2^{\frac{2}{3}}} = \frac{2^{\frac{5}{2}}}{2^{\frac{2}{3}}} = 2^{\frac{5}{2} - \frac{2}{3}} = 2^{\frac{11}{6}}$

$\Rightarrow \sqrt[3]{\frac{2 \sqrt{8}}{\sqrt[3]{4}}} = \sqrt[3]{2^{\frac{11}{6}}} = 2^{\frac{11}{6} \div 3} = 2^{\frac{11}{18}}$

Ta xét từ trong căng rồi tới bên ngoài :))

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Answer 4

$\frac{\sqrt[3]{2 \sqrt{8}}}{\sqrt[3]{\sqrt[3]{4}}} = \sqrt[3]{\frac{2 \sqrt{8}}{\sqrt[3]{4}}} - X é t \frac{2 \sqrt{2^{3}}}{\sqrt[3]{2^{2}}} = \frac{2 x 2^{\frac{3}{2}}}{2^{\frac{2}{3}}} = \frac{2^{\frac{5}{2}}}{2^{\frac{2}{3}}} = 2^{\frac{5}{2} - \frac{2}{3}} = 2^{\frac{11}{6}}$

$\Rightarrow \sqrt[3]{\frac{2 \sqrt{8}}{\sqrt[3]{4}}} = \sqrt[3]{2^{\frac{11}{6}}} = 2^{\frac{11}{6} \div 3} = 2^{\frac{11}{18}}$

Ta xét từ trong căng rồi tới bên ngoài :))

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