Question

Đã trả lời bởi chuyên gia

Answer 1

$a, \frac{5}{7} - \frac{1}{2} + \frac{3}{14} = \frac{10}{14} - \frac{7}{14} + \frac{3}{14} = \frac{6}{14} = \frac{3}{7} b, (\frac{103}{5} + \frac{5}{3}) - \frac{98}{5} = \frac{103}{5} + \frac{5}{3} - \frac{98}{5} = (\frac{103}{5} - \frac{98}{5}) + \frac{5}{3} = 1 + \frac{5}{3} = \frac{3}{3} + \frac{5}{3} = \frac{8}{3} c, \frac{8}{13} + \frac{- 7}{11} + \frac{5}{13} + \frac{- 4}{11} = (\frac{8}{13} + \frac{5}{13}) + (\frac{- 7}{11} - \frac{4}{11}) = 1 + (- 1) = 0$

$d, 125 % : \frac{1}{3} + \frac{7}{3} . (\frac{- 1}{2}) = \frac{5}{4} . 3 + \frac{- 7}{6} = \frac{15}{4} - \frac{7}{6} = \frac{90}{24} - \frac{28}{24} = \frac{62}{24} = \frac{31}{12}$ .

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Answer 2

$a, \frac{5}{7} - \frac{1}{2} + \frac{3}{14} = \frac{10}{14} - \frac{7}{14} + \frac{3}{14} = \frac{6}{14} = \frac{3}{7} b, (\frac{103}{5} + \frac{5}{3}) - \frac{98}{5} = \frac{103}{5} + \frac{5}{3} - \frac{98}{5} = (\frac{103}{5} - \frac{98}{5}) + \frac{5}{3} = 1 + \frac{5}{3} = \frac{3}{3} + \frac{5}{3} = \frac{8}{3} c, \frac{8}{13} + \frac{- 7}{11} + \frac{5}{13} + \frac{- 4}{11} = (\frac{8}{13} + \frac{5}{13}) + (\frac{- 7}{11} - \frac{4}{11}) = 1 + (- 1) = 0$

$d, 125 % : \frac{1}{3} + \frac{7}{3} . (\frac{- 1}{2}) = \frac{5}{4} . 3 + \frac{- 7}{6} = \frac{15}{4} - \frac{7}{6} = \frac{90}{24} - \frac{28}{24} = \frac{62}{24} = \frac{31}{12}$ .

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