Question

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Answer 1

$n_{A l} = 0, 1 m o l m_{H C l} = 7, 3 g = > n_{H C l} = 0, 2 m o l V ì n_{A l} > \frac{1}{3} n_{H C l} n ê n A l d ư 2 A l + 6 H C l - > 2 A l C l_{3_{}} + 3 H_{2} \frac{0, 2}{3} 0, 2 \frac{0, 2}{3} 0, 1 m d d = m_{A l p / u} + m_{d d H C l} - m_{H_{2}} = 38, 1 g m_{A l C l_{3} = 8, 9 g} C % A l C l_{3} = 8, 9 : 38, 1.100 = 23.36 %$

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Answer 2

$n_{A l} = 0, 1 m o l m_{H C l} = 7, 3 g = > n_{H C l} = 0, 2 m o l V ì n_{A l} > \frac{1}{3} n_{H C l} n ê n A l d ư 2 A l + 6 H C l - > 2 A l C l_{3_{}} + 3 H_{2} \frac{0, 2}{3} 0, 2 \frac{0, 2}{3} 0, 1 m d d = m_{A l p / u} + m_{d d H C l} - m_{H_{2}} = 38, 1 g m_{A l C l_{3} = 8, 9 g} C % A l C l_{3} = 8, 9 : 38, 1.100 = 23.36 %$

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Answer 3

$2 A l + 6 H C l - > 2 A l C l_{3} + 3 H_{2} n A l = \frac{2, 7}{27} = 0, 1 m o l m H C l = 36, 5.0, 2 = 7, 3 g = > n H C l = \frac{7, 3}{36, 5} = 0, 2 m o l = > S a u p ư t h ì A l d ư v à H C l h ế t = > n A l p ư = \frac{n H C l}{3} = \frac{1}{15} m o l = > m A l p ư = 1, 8 g = > n A l C l_{3} = \frac{1}{15} m o l = > m A l C l_{3} = 8, 9 g n H_{2} = 0, 5 . n H C l = 0, 5.0, 2 = 0, 1 m o l = > m H_{2} = 0, 1.2 = 0, 2 g = > m d d s a u = 1, 8 + 36, 5 - 0, 2 = 38, 1 g = > C % A l C l_{3} = \frac{8, 9}{38, 1} . 100 % = 23.36 %$

Vậy 23,36%

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Answer 4

$2 A l + 6 H C l - > 2 A l C l_{3} + 3 H_{2} n A l = \frac{2, 7}{27} = 0, 1 m o l m H C l = 36, 5.0, 2 = 7, 3 g = > n H C l = \frac{7, 3}{36, 5} = 0, 2 m o l = > S a u p ư t h ì A l d ư v à H C l h ế t = > n A l p ư = \frac{n H C l}{3} = \frac{1}{15} m o l = > m A l p ư = 1, 8 g = > n A l C l_{3} = \frac{1}{15} m o l = > m A l C l_{3} = 8, 9 g n H_{2} = 0, 5 . n H C l = 0, 5.0, 2 = 0, 1 m o l = > m H_{2} = 0, 1.2 = 0, 2 g = > m d d s a u = 1, 8 + 36, 5 - 0, 2 = 38, 1 g = > C % A l C l_{3} = \frac{8, 9}{38, 1} . 100 % = 23.36 %$

Vậy 23,36%

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