Question

Đã trả lời bởi chuyên gia

Answer 1

a) Ta có: $\frac{1}{2} + \frac{3}{2} x = \frac{11}{6}$
=> $\frac{3}{2} x = \frac{11}{6} - \frac{1}{2} = \frac{11}{6} - \frac{3}{6} = \frac{8}{6} = \frac{4}{3}$
=> x = $\frac{4}{3} : \frac{3}{2} = \frac{4}{3} \times \frac{3}{2} = \frac{8}{9}$
b) Ta có: $\frac{3}{2} x - \frac{1}{2} = \frac{1}{6}$
=> $\frac{3}{2} x = \frac{1}{6} + \frac{1}{2} = \frac{1}{6} + \frac{3}{6} = \frac{4}{6} = \frac{2}{3}$
=> x = $\frac{2}{3} : \frac{3}{2} = \frac{2}{3} \times \frac{2}{3} = \frac{4}{9}$
c) Ta có: $\frac{1}{2} + \frac{3}{4} x = - \frac{1}{8}$
=> $\frac{3}{4} x = - \frac{1}{8} - \frac{1}{2} = - \frac{1}{8} - \frac{4}{8} = \frac{- 5}{8}$
=> $x = - \frac{5}{8} : \frac{3}{4} = - \frac{5}{8} \times \frac{4}{3} = - \frac{5}{6}$
d) Ta có: $\frac{2}{3} x + \frac{1}{5} = - \frac{4}{3}$
=> $\frac{2}{3} x = - \frac{4}{3} - \frac{1}{5} = - \frac{20}{15} - \frac{3}{15} = - \frac{23}{15}$
=> x = $- \frac{23}{15} : \frac{2}{3} = - \frac{23}{15} \times \frac{3}{2} = - \frac{23}{10}$

...Xem thêm

Answer 2

a) Ta có: $\frac{1}{2} + \frac{3}{2} x = \frac{11}{6}$
=> $\frac{3}{2} x = \frac{11}{6} - \frac{1}{2} = \frac{11}{6} - \frac{3}{6} = \frac{8}{6} = \frac{4}{3}$
=> x = $\frac{4}{3} : \frac{3}{2} = \frac{4}{3} \times \frac{3}{2} = \frac{8}{9}$
b) Ta có: $\frac{3}{2} x - \frac{1}{2} = \frac{1}{6}$
=> $\frac{3}{2} x = \frac{1}{6} + \frac{1}{2} = \frac{1}{6} + \frac{3}{6} = \frac{4}{6} = \frac{2}{3}$
=> x = $\frac{2}{3} : \frac{3}{2} = \frac{2}{3} \times \frac{2}{3} = \frac{4}{9}$
c) Ta có: $\frac{1}{2} + \frac{3}{4} x = - \frac{1}{8}$
=> $\frac{3}{4} x = - \frac{1}{8} - \frac{1}{2} = - \frac{1}{8} - \frac{4}{8} = \frac{- 5}{8}$
=> $x = - \frac{5}{8} : \frac{3}{4} = - \frac{5}{8} \times \frac{4}{3} = - \frac{5}{6}$
d) Ta có: $\frac{2}{3} x + \frac{1}{5} = - \frac{4}{3}$
=> $\frac{2}{3} x = - \frac{4}{3} - \frac{1}{5} = - \frac{20}{15} - \frac{3}{15} = - \frac{23}{15}$
=> x = $- \frac{23}{15} : \frac{2}{3} = - \frac{23}{15} \times \frac{3}{2} = - \frac{23}{10}$

Answer 3

Mình giải từng câu nha ✏️?

a) 12+32x=116\dfrac{1}{2} + \dfrac{3}{2}x = \dfrac{11}{6}21+23x=611
Ta có:

32x=116−12\dfrac{3}{2}x = \dfrac{11}{6} - \dfrac{1}{2}23x=611−21Quy đồng 12=36\dfrac{1}{2} = \dfrac{3}{6}21=63

32x=116−36=86=43\dfrac{3}{2}x = \dfrac{11}{6} - \dfrac{3}{6} = \dfrac{8}{6} = \dfrac{4}{3}23x=611−63=68=34 x=43:32x = \dfrac{4}{3} : \dfrac{3}{2}x=34:23 x=43×23=89x = \dfrac{4}{3} \times \dfrac{2}{3} = \dfrac{8}{9}x=34×32=98✅ x = 8/9

b) 32x−12=16\dfrac{3}{2}x - \dfrac{1}{2} = \dfrac{1}{6}23x−21=61
32x=16+12\dfrac{3}{2}x = \dfrac{1}{6} + \dfrac{1}{2}23x=61+21Quy đồng 12=36\dfrac{1}{2} = \dfrac{3}{6}21=63

32x=16+36=46=23\dfrac{3}{2}x = \dfrac{1}{6} + \dfrac{3}{6} = \dfrac{4}{6} = \dfrac{2}{3}23x=61+63=64=32 x=23:32x = \dfrac{2}{3} : \dfrac{3}{2}x=32:23 x=23×23=49x = \dfrac{2}{3} \times \dfrac{2}{3} = \dfrac{4}{9}x=32×32=94✅ x = 4/9

c) 12+34x=−18\dfrac{1}{2} + \dfrac{3}{4}x = -\dfrac{1}{8}21+43x=−81
34x=−18−12\dfrac{3}{4}x = -\dfrac{1}{8} - \dfrac{1}{2}43x=−81−21Quy đồng 12=48\dfrac{1}{2} = \dfrac{4}{8}21=84

34x=−18−48=−58\dfrac{3}{4}x = -\dfrac{1}{8} - \dfrac{4}{8} = -\dfrac{5}{8}43x=−81−84=−85 x=−58:34x = -\dfrac{5}{8} : \dfrac{3}{4}x=−85:43 x=−58×43=−2024=−56x = -\dfrac{5}{8} \times \dfrac{4}{3} = -\dfrac{20}{24} = -\dfrac{5}{6}x=−85×34=−2420=−65✅ x = -5/6

d) 23x+15=−43\dfrac{2}{3}x + \dfrac{1}{5} = -\dfrac{4}{3}32x+51=−34
23x=−43−15\dfrac{2}{3}x = -\dfrac{4}{3} - \dfrac{1}{5}32x=−34−51Quy đồng mẫu 15:

−43=−2015-\dfrac{4}{3} = -\dfrac{20}{15}−34=−1520 15=315\dfrac{1}{5} = \dfrac{3}{15}51=153 23x=−2015−315=−2315\dfrac{2}{3}x = -\dfrac{20}{15} - \dfrac{3}{15} = -\dfrac{23}{15}32x=−1520−153=−1523 x=−2315:23x = -\dfrac{23}{15} : \dfrac{2}{3}x=−1523:32 x=−2315×32=−6930=−2310x = -\dfrac{23}{15} \times \dfrac{3}{2} = -\dfrac{69}{30} = -\dfrac{23}{10}x=−1523×23=−3069=−1023✅ x = -23/10

Nếu cần mình giải theo kiểu trình bày "Lời giải" đầy đủ để chép vào vở thì nói mình nha ?✨

...Xem thêm

Answer 4