To solve the problem, we need to find the mass of hydrogen (m) produced when sodium bicarbonate reacts with calcium carbonate.

From the reaction between sodium bicarbonate (NaHCO₃) and calcium carbonate (CaCO₃):

The mass of sodium bicarbonate used is 22 g.
The molar mass of NaHCO₃ is approximately 84 g/mol.
The number of moles of NaHCO₃ is n=22 g84 g/mol≈0.26 moln=84g/mol22g​≈0.26mol.
The balanced chemical equation indicates that hydrogen (H₂) is produced, but it is important to know how much hydrogen gas is expected based on the stoichiometry of the reaction.
It's stated that you get 15 g of carbon (C), which may imply that excess reactants or another limit is at play.
From the reaction, the hydrogen produced can be calculated from the context given, which flows from the law of conservation of mass.
After calculating using the stoichiometric coefficients (which would require the full equation), the calculated m can be found.
You can conclude this with the produced mass of hydrogen given the final yield and initial substances which will involve solving