Biết \[\frac{{{\rm{x + 3}}}}{{{{\rm{x}}^{\rm{2}}} - {\rm{4}}}}{\rm{.}}\frac{{{\rm{8}} - {\rm{12x + 6}}{{\rm{x}}^{\rm{2}}} - {{\rm{x}}^{\rm{3}}}}}{{{\rm{9x + 27}}}}{\rm{ = }} - \frac{{\rm{A}}}{{\rm{B}}}\]. Tìm A, B.
A. \[{\rm{A = }}{\left( {{\rm{x}} - {\rm{2}}} \right)^{\rm{2}}}{\rm{;}}\,\,{\rm{B = 9}}\left( {{\rm{x + 2}}} \right)\]
B. \[{\rm{A = 9}}\left( {{\rm{x + 2}}} \right){\rm{;}}\,\,{\rm{B = }}{\left( {{\rm{x}} - {\rm{2}}} \right)^{\rm{2}}}\]
C. \[{\rm{A = 9}}\left( {{\rm{x}} - {\rm{2}}} \right){\rm{;}}\,\,{\rm{B = }}{\left( {{\rm{x + 2}}} \right)^{\rm{2}}}\]
D. \[{\rm{A = }}{\left( {{\rm{x + 2}}} \right)^{\rm{2}}}{\rm{;}}\,\,{\rm{B = 9}}\left( {{\rm{x}} - {\rm{2}}} \right)\]