Question

Đã trả lời bởi chuyên gia

Answer 1

$a, {(x + 5)}^{3} - x . (x + 3) (x - 3) - 15 x^{2} = 303 < = > x^{3} + 15 x^{2} + 75 x + 125 - x . (x^{2} - 9) - 15 x^{2} = 303 < = > x^{3} + 75 x + 125 - x^{3} + 9 x = 303 < = > 84 x + 125 = 303 < = > 84 x = 303 - 125 < = > 84 x = 178 < = > x = \frac{89}{42} V ậ y x = \frac{89}{42}$

$b, {(x + 2)}^{3} - x^{2} . (x + 6) = 68 < = > x^{3} + 6 x^{2} + 12 x + 8 - x^{3} - 6 x^{2} = 68 < = > 12 x + 8 = 68 < = > 12 x = 60 < = > x = 5 V ậ y x = 5 c, {(x + 1)}^{3} + {(x + 2)}^{3} + 3 . (x + 1) (x - 1) = - 37 < = > x^{3} + 3 x^{2} + 3 x + 1 + x^{3} + 6 x^{2} + 12 x + 8 + 3 x^{2} - 3 = - 37 < = > 2 x^{3} + 12 x^{2} + 15 x + 43 = 0 < = > x \approx - 5, 35 V ậ y x \approx - 5, 35$

$d, (2 x + 1) - 8 x . {(x + 3)}^{2} + (6 x - 1) (1 + 6 x) = 96 x^{2} + 66 < = > 2 x + 1 - 8 x . (x^{2} + 6 x + 9) + 36 x^{2} - 1 = 96 x^{2} + 66 < = > 2 x + 1 - 8 x^{3} - 48 x^{2} - 72 x + 36 x^{2} - 1 - 96 x^{2} - 66 = 0 < = > - 8 x^{3} - 108 x^{2} - 70 x - 66 = 0 < = > x \approx - 12, 87 V ậ y x \approx - 12, 87$ .

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Answer 2

$a, {(x + 5)}^{3} - x . (x + 3) (x - 3) - 15 x^{2} = 303 < = > x^{3} + 15 x^{2} + 75 x + 125 - x . (x^{2} - 9) - 15 x^{2} = 303 < = > x^{3} + 75 x + 125 - x^{3} + 9 x = 303 < = > 84 x + 125 = 303 < = > 84 x = 303 - 125 < = > 84 x = 178 < = > x = \frac{89}{42} V ậ y x = \frac{89}{42}$

$b, {(x + 2)}^{3} - x^{2} . (x + 6) = 68 < = > x^{3} + 6 x^{2} + 12 x + 8 - x^{3} - 6 x^{2} = 68 < = > 12 x + 8 = 68 < = > 12 x = 60 < = > x = 5 V ậ y x = 5 c, {(x + 1)}^{3} + {(x + 2)}^{3} + 3 . (x + 1) (x - 1) = - 37 < = > x^{3} + 3 x^{2} + 3 x + 1 + x^{3} + 6 x^{2} + 12 x + 8 + 3 x^{2} - 3 = - 37 < = > 2 x^{3} + 12 x^{2} + 15 x + 43 = 0 < = > x \approx - 5, 35 V ậ y x \approx - 5, 35$

$d, (2 x + 1) - 8 x . {(x + 3)}^{2} + (6 x - 1) (1 + 6 x) = 96 x^{2} + 66 < = > 2 x + 1 - 8 x . (x^{2} + 6 x + 9) + 36 x^{2} - 1 = 96 x^{2} + 66 < = > 2 x + 1 - 8 x^{3} - 48 x^{2} - 72 x + 36 x^{2} - 1 - 96 x^{2} - 66 = 0 < = > - 8 x^{3} - 108 x^{2} - 70 x - 66 = 0 < = > x \approx - 12, 87 V ậ y x \approx - 12, 87$ .

Answer 3

x≈−12,87d, 2x+1-8x.x+32+6x-11+6x=96x2+66<=>2x+1-8x.x2+6x+9+36x2-1=96x2+66<=>2x+1-8x3-48x2-72x+36x2-1-96x2-66=0<=>-8x3-108x2-70x-66=0<=>x≈-12,87Vậy x≈-12,87.

Answer 4

đó mà toán lớp 1

Answer 5

x≈-12,87

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