Quảng cáo
6 câu trả lời 593
a,PTHH:Fe+H2SO4→FeSO4+H2↑b,nFe=5,656=0,1 (mol).Theo pt: nH2=nFe=0,1 (mol).⇒VH2=0,1×22,4=2,24 (l).c,Theo pt: nH2SO4=nFe=0,1 (mol).Vdd H2SO4=50 (ml)=0,05 (l).⇒CMdd H2SO4=0,10,05=2 (M)..
học tốt nhé!
a,PTHH:Fe+H2SO4→FeSO4+H2↑b,nFe=5,656=0,1 (mol).Theo pt: nH2=nFe=0,1 (mol).⇒VH2=0,1×22,4=2,24 (l).c,Theo pt: nH2SO4=nFe=0,1 (mol).Vdd H2SO4=50 (ml)=0,05 (l).⇒CMdd H2SO4=0,10,05=2 (M).a,PTHH:Fe+H2SO4→FeSO4+H2↑b,nFe=5,656=0,1 (mol).Theo pt: nH2=nFe=0,1 (mol).⇒VH2=0,1×22,4=2,24 (l).c,Theo pt: nH2SO4=nFe=0,1 (mol).Vdd H2SO4=50 (ml)=0,05 (l).⇒CMdd H2SO4=0,10,05=2 (M)..
a,PTHH:Fe+H2SO4→FeSO4+H2↑b,nFe=5,656=0,1 (mol).Theo pt: nH2=nFe=0,1 (mol).⇒VH2=0,1×22,4=2,24 (l).c,Theo pt: nH2SO4=nFe=0,1 (mol).Vdd H2SO4=50 (ml)=0,05 (l).⇒CMdd H2SO4=0,10,05=2 (M).a,PTHH:Fe+H2SO4→FeSO4+H2↑b,nFe=5,656=0,1 (mol).Theo pt: nH2=nFe=0,1 (mol).⇒VH2=0,1×22,4=2,24 (l).c,Theo pt: nH2SO4=nFe=0,1 (mol).Vdd H2SO4=50 (ml)=0,05 (l).⇒CMdd H2SO4=0,10,05=2 (M)..
học tốt nhé!
a,PTHH:Fe+H2SO4→FeSO4+H2↑b,nFe=5,656=0,1 (mol).Theo pt: nH2=nFe=0,1 (mol).⇒VH2=0,1×22,4=2,24 (l).c,Theo pt: nH2SO4=nFe=0,1 (mol).Vdd H2SO4=50 (ml)=0,05 (l).⇒CMdd H2SO4=0,10,05=2 (M).a,PTHH:Fe+H2SO4→FeSO4+H2↑b,nFe=5,656=0,1 (mol).Theo pt: nH2=nFe=0,1 (mol).⇒VH2=0,1×22,4=2,24 (l).c,Theo pt: nH2SO4=nFe=0,1 (mol).Vdd H2SO4=50 (ml)=0,05 (l).⇒CMdd H2SO4=0,10,05=2 (M)..
học tốt nhé!
a,PTHH:Fe+H2SO4→FeSO4+H2↑b,nFe=5,656=0,1 (mol).Theo pt: nH2=nFe=0,1 (mol).⇒VH2=0,1×22,4=2,24 (l).c,Theo pt: nH2SO4=nFe=0,1 (mol).Vdd H2SO4=50 (ml)=0,05 (l).⇒CMdd H2SO4=0,10,05=2 (M).a,PTHH:Fe+H2SO4→FeSO4+H2↑b,nFe=5,656=0,1 (mol).Theo pt: nH2=nFe=0,1 (mol).⇒VH2=0,1×22,4=2,24 (l).c,Theo pt: nH2SO4=nFe=0,1 (mol).Vdd H2SO4=50 (ml)=0,05 (l).⇒CMdd H2SO4=0,10,05=2 (M)..
học tốt nhé!
Quảng cáo