Quảng cáo
1 câu trả lời 129
* Phương trình hoá học:
* Cơ chế phản ứng: Phản ứng trên xảy ra theo cơ chế thế gốc (SR), gồm ba giai đoạn chính như sau:
- Giai đoạn khơi mào phản ứng:
- Giai đoạn phát triển mạch phản ứng:
\(C{H_3} - C{H_2} - C{H_2} - H + B{r^ \bullet } \to C{H_3} - C{H_2} - \mathop C\limits^ \bullet {H_2} + HBr\)
\(C{H_3} - C{H_2} - \mathop C\limits^ \bullet {H_2} + Br - Br \to C{H_3} - C{H_2} - C{H_2} - Br + B{r^ \bullet }\)
\[\begin{array}{l}C{H_3} - \mathop C\limits_{\left| {} \right.} H - C{H_3} + B{r^ \bullet } \to C{H_3} - \mathop C\limits^ \bullet H - C{H_3} + HBr\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,H\end{array}\]
\(\begin{array}{l}C{H_3} - \mathop C\limits^ \bullet H - C{H_3} + Br - Br \to C{H_3} - \mathop C\limits_{\left| {} \right.} H - C{H_3} + B{r^ \bullet }\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\end{array}\)
…..
- Giai đoạn tắt mạch phản ứng:
\(B{r^ \bullet } + {}^ \bullet Br \to Br - Br\)
\(C{H_3} - C{H_2} - \mathop C\limits^ \bullet {H_2} + B{r^ \bullet } \to C{H_3} - C{H_2} - C{H_2} - Br\)
\(\begin{array}{l}C{H_3} - \mathop C\limits^ \bullet H - C{H_3} + B{r^ \bullet } \to C{H_3} - \mathop C\limits_{\left| {} \right.} H - C{H_3}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\end{array}\)
\(C{H_3} - C{H_2} - \mathop C\limits^ \bullet {H_2} + \mathop C\limits^ \bullet {H_2} - C{H_2} - C{H_3} \to C{H_3} - C{H_2} - C{H_2} - C{H_2} - C{H_2} - C{H_3}\)
\[\begin{array}{l}C{H_3} - C{H_2} - \mathop C\limits^ \bullet {H_2} + C{H_3} - \mathop C\limits^ \bullet H - C{H_3} \to C{H_3} - C{H_2} - C{H_2} - \mathop C\limits_{\left| {} \right.} H - C{H_3}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\end{array}\]
\(\begin{array}{l}C{H_3} - \mathop C\limits^ \bullet H - C{H_3} + C{H_3} - \mathop C\limits^ \bullet H - C{H_3} \to C{H_3} - \mathop C\limits_{\left| {} \right.} H - \mathop C\limits_{\left| {} \right.} H - C{H_3}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,\,\,\,C{H_3}\end{array}\)
* Dự đoán sản phẩm chính:
\[\begin{array}{l}C{H_3} - \mathop C\limits_{\left| {} \right.} H - C{H_3}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\\2{\rm{ }}--{\rm{ }}bromopropane\end{array}\]
Do trong phản ứng thế gốc vào nguyên tử carbon no của alkane, nguyên tử hydrogen liên kết với nguyên tử carbon bậc cao hơn sẽ dễ bị thế hơn do tạo gốc tự do bền hơn.
Quảng cáo
Bạn cần hỏi gì?
Câu hỏi hot cùng chủ đề
-
Đã trả lời bởi chuyên gia
96145 -
Đã trả lời bởi chuyên gia
83786 -
Đã trả lời bởi chuyên gia
73477 -
Đã trả lời bởi chuyên gia
51724
