Question

Đã trả lời bởi chuyên gia

Answer 1

Chọn đáp án A

$\begin{array}{l} + n_{T} = \frac{2, 688}{22, 4} = 0, 12 \Rightarrow n_{C O_{2}} = 0, 05; n_{H_{2}} = 0, 02; n_{N O} = 0, 05 \Rightarrow n_{F e C O_{3}} = n_{C O_{2}} = 0, 05 . \\ + n_{H^{+} t r o n g Z} = n_{H C l} - 2 n_{C O_{2}} - 2 n_{H_{2}} - 4 n_{N O} = 0, 06 \Rightarrow Z + A g N O_{3} \to n_{N O} = \frac{0, 06}{4} = 0, 015 \\ \begin{array}{l} + T c h ¨ o ̀ u a H_{2} \Rightarrow N {O_{3}}^{-} ~ n a ~ o h e ́ a t \\ + n_{A l} = x; n_{F e {(N O_{3})}_{2}} = y; n_{K N O_{3}} = z \end{array}\} \Rightarrow Z \overset{0, 45 m o l N a O H}{\to} d d \{\begin{array}{l} K^{+} : z m o l \\ N a^{+} : 0, 45 m o l \\ C l^{-} : 0, 4 m o l \\ A l {O_{2}}^{-} : x m o l \end{array}\} (*) \\ \Rightarrow \{\begin{cases} B T ~ N T c h o (*) : 0, 45 + z = 0, 4 + x \\ m_{X} = 27 x + 180 y + 0, 05.116 = 11, 02 \\ B T N T N : 2 y + z = 0, 05 \end{cases} \Rightarrow \{\begin{cases} x = 0, 06 \\ y = 0, 02 \\ z = 0, 01 \end{cases} \\ \begin{array}{l} + B T E c h o t o a \ o n b o ¨ a q u a ̀ u t r ̀ i n h : 3 \underset{0, 06}{\underset{⏟}{n_{A l}}} + \underset{0, 02}{\underset{⏟}{n_{F e {(N O_{3})}_{2}}}} + \underset{0, 05}{\underset{⏟}{n_{F e C O_{3}}}} = 2 \underset{0, 02}{\underset{⏟}{n_{H_{2}}}} + 3 \underset{0, 065}{\underset{⏟}{n_{N O}}} + \underset{?}{\underset{⏟}{n_{A g^{+} p ¨ o}}} \Rightarrow n_{A g^{+} p ¨ o} = 0, 015 \\ \Rightarrow m_{k e ́ a t t u^u a} = m_{A g} + m_{A g C l} = 0, 015.108 + 0, 4.143, 5 = 59, 02 g a m . \end{array} \end{array}$

...Xem thêm

Answer 2

Chọn đáp án A

$\begin{array}{l} + n_{T} = \frac{2, 688}{22, 4} = 0, 12 \Rightarrow n_{C O_{2}} = 0, 05; n_{H_{2}} = 0, 02; n_{N O} = 0, 05 \Rightarrow n_{F e C O_{3}} = n_{C O_{2}} = 0, 05 . \\ + n_{H^{+} t r o n g Z} = n_{H C l} - 2 n_{C O_{2}} - 2 n_{H_{2}} - 4 n_{N O} = 0, 06 \Rightarrow Z + A g N O_{3} \to n_{N O} = \frac{0, 06}{4} = 0, 015 \\ \begin{array}{l} + T c h ¨ o ̀ u a H_{2} \Rightarrow N {O_{3}}^{-} ~ n a ~ o h e ́ a t \\ + n_{A l} = x; n_{F e {(N O_{3})}_{2}} = y; n_{K N O_{3}} = z \end{array}\} \Rightarrow Z \overset{0, 45 m o l N a O H}{\to} d d \{\begin{array}{l} K^{+} : z m o l \\ N a^{+} : 0, 45 m o l \\ C l^{-} : 0, 4 m o l \\ A l {O_{2}}^{-} : x m o l \end{array}\} (*) \\ \Rightarrow \{\begin{cases} B T ~ N T c h o (*) : 0, 45 + z = 0, 4 + x \\ m_{X} = 27 x + 180 y + 0, 05.116 = 11, 02 \\ B T N T N : 2 y + z = 0, 05 \end{cases} \Rightarrow \{\begin{cases} x = 0, 06 \\ y = 0, 02 \\ z = 0, 01 \end{cases} \\ \begin{array}{l} + B T E c h o t o a \ o n b o ¨ a q u a ̀ u t r ̀ i n h : 3 \underset{0, 06}{\underset{⏟}{n_{A l}}} + \underset{0, 02}{\underset{⏟}{n_{F e {(N O_{3})}_{2}}}} + \underset{0, 05}{\underset{⏟}{n_{F e C O_{3}}}} = 2 \underset{0, 02}{\underset{⏟}{n_{H_{2}}}} + 3 \underset{0, 065}{\underset{⏟}{n_{N O}}} + \underset{?}{\underset{⏟}{n_{A g^{+} p ¨ o}}} \Rightarrow n_{A g^{+} p ¨ o} = 0, 015 \\ \Rightarrow m_{k e ́ a t t u^u a} = m_{A g} + m_{A g C l} = 0, 015.108 + 0, 4.143, 5 = 59, 02 g a m . \end{array} \end{array}$

1 câu trả lời 234

Câu hỏi hot cùng chủ đề

Bài viết mới nhất Lớp 12