Bạn vẽ hình giúp mình nhé.a, theo định lý đường phân giác ta có:DBAB=DCAC⇔DBDC=ABAC=6/8=3/4xét ΔABC, theo định lý pitago, ta có:BC2=AB2+AC2=62+82=100BC=10 cmTa có:DBAB=DCAC=BCAB+AC=106+8=57suy ra DB6=57⇒DB=30/7 cmDC8=57⇒DC=40/7 cmb, xét ΔABC có DE∥AC nên theo định lý talet ta có:DBBC=DEAC=BEBA⇔30/710=DE8=BE6⇒DE=24/7 cm và BE=18/7 cm⇒AE=6−18/7=24/7 cmxét tứ giác AEDC có (AE⊥AC; AE⊥DE) nên AEDC là hình thang vuông.diện tích hình thang AEDC=12 (DE+AC).AE=12.(247+8).247=96049cm2c, Do DE∥AC nên ta có:OEOC=ODOA⇒OEOC+OE=ODOA+OD⇔OEEC=OD AD     (1)xét ΔEAC có NO∥AC nên ONAC=EOEC      (2)xét ΔADC có OM∥AC nên OMAC=DODA       (3)từ (1) (2) và (3) suy ra OM=ON (đpcm)

Đặt câu hỏi cho từ in đậm:

1. Peter go to the library twice a week.

-> How often does Peter go to the library?

2. Peter and Mike are playing football.

-> What are Peter and Mike playing?

3. This dress costs 150 dollars.

-> How much does this dress cost?

4. She speaks English fluently.

-> How does she speak English?

5. Columbus lives America.

-> Where does Columbus live?